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Annette [7]
3 years ago
8

Join if u r free id pass in bio​

Physics
1 answer:
Basile [38]3 years ago
3 0

Answer:

folllow

Explanation:

soon soon gs a ayre j will join meet

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Help I need an answer!
Umnica [9.8K]

You apparently haven't noticed yet . . .

The moon rises in the East, moves across the sky, and sets
in the West, just like the sun and everything else in the sky.

It takes the moon about 12 hours and 25 minutes to go from
rising to setting, and then it rises again about 24 hours and
49 minutes later.  So each day, the moon rises about 49 minutes
later than it rose on the previous day.

In order to describe the direction and height of the moon in the sky,
you need to tell the date and the time, and also the latitude on Earth
from which you observed it.  And wherever the moon was in the sky
at that time, it was in a noticeably different place 30 minutes later.

Just like the sun.

5 0
3 years ago
Is a dog barking an example of kinetic energy to potential energy
Pepsi [2]
It is not an example of kinetic to potential because the dog is already in motion rather then having the potential to do something. Hope this helps!
3 0
2 years ago
If the range of the projectile is 4.3 m, the time-of-flight is T = 0.829 s, and air resistance is negligible, determine the foll
ankoles [38]

Answer

given,

range of the projectile = 4.3 m

time of flight = T = 0.829 s

v =\dfrac{d}{T}

v =\dfrac{4.3}{0.829}

     v = 5.19 m/s

vertical component of velocity of projectile

v_y = gt'

v_y = 9.8 \times {\dfrac{T}{2}}

v_y = 9.8 \times {\dfrac{0.829}{2}}

v_y =4.06\ m/s

a) Launch angle

 \theta = tan^{-1}(\dfrac{v_y}{v})

 \theta = tan^{-1}(\dfrac{4.06}{5.19})

    θ = 38°

b) initial speed of projectile

  v = \sqrt{v_x^2 + v_y^2}

  v = \sqrt{5.19^2 + 4.06^2}

         v = 6.59 m/s

c) maximum height reached by the projectile

     y_{max}=v_{avg}t'

     y_{max}=\dfrac{1}{2}v_y\dfrac{T}{2}

     y_{max}=\dfrac{1}{2}\times(g\dfrac{T}{2})\times\dfrac{T}{2}

     y_{max}=\dfrac{gT^2}{8}          

7 0
4 years ago
In the visible light portion of the electromagnetic spectrum, each __________ is determined by its wavelength.
Archy [21]

Answer:

A) color

Explanation:

Visible light is a portion of the electromagnetic spectrum, that includes wavelengths approximately from 380 nm to 750 nm.

It is the only part of the electromagnetic spectrum that the human eye can see. Depending on the wavelength of the light in this region, we perceive the light as a different color.

Therefore, each color is associated to a different range of wavelength, as follows:

Violet 380 - 450 nm

Blue 450 - 495 nm

Green 495 - 570 nm

Yellow 570 - 590 nm

Orange 590 - 620 nm

Red 620 - 750 nm

6 0
3 years ago
Monochromatic light falls on two very narrow slits 0.047 mm apart. Successive fringes on a screen 6.60 m away are 8.9 cm apart n
Svet_ta [14]

Answer::

   \lambda  =  634 nm

  f =  4.73 *10^{14} \  Hz

Explanation:

From the question we are told that

      The  distance of separation is  d =  0.047 \ mm =  0.047 *10^{-3} \ m

       The  distance of the screen is  D =  6.60 \ m

      The  width of the fringe is y  =  8.9 \ cm  =  0.089 \ m

     

Generally the width of the width of the fringes is mathematically represented as

          y  = \frac{\lambda  *  D }{d }

=>       \lambda  =  \frac{y *  d }{D }

=>      \lambda  =  \frac{ 0.089  *   (0.047 *10^{-3}) }{6.60  }

=>    \lambda  =  634 *10^{-9}

=>  \lambda  =  634 nm

Generally the speed of light is mathematically represented as

         c  =  f * \lambda

=>       f=  \frac{ c}{\lambda }

=>         f=  \frac{ 3.0 *10^{8}}{634 *10^{-9}}

=>     f =  4.73 *10^{14} \  Hz

6 0
3 years ago
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