Answer:
Part 1) see the procedure
Part 2) 
Part 3) 
Part 4) The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months
Step-by-step explanation:
Part 1) Define a variable for the situation.
Let 
x ------> the number of months
y ----> the total cost monthly for website hosting
Part 2) Write an inequality that represents the situation.
we know that
Site A

Site B

The inequality that represent this situation is

Part 3) Solve the inequality to find out how many months he needs to keep the website for Site A to be less expensive than Site B

Subtract 4.95x both sides


Divide by 5 both sides


Rewrite

Part 4) describe how many months he needs to keep the website for Site A to be less expensive than Site B. 
The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months
 
        
             
        
        
        
If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show

Let  . Compute the inverse:
. Compute the inverse:
![f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}](https://tex.z-dn.net/?f=f%5Cleft%28f%5E%7B-1%7D%28x%29%5Cright%29%20%3D%20%5Csqrt%7B1%20%2B%20f%5E%7B-1%7D%28x%29%5E3%7D%20%3D%20x%20%5Cimplies%20f%5E%7B-1%7D%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%5E2-1%7D)
and we immediately notice that ![f^{-1}(x+1)=\sqrt[3]{x^2+2x}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%2B1%29%3D%5Csqrt%5B3%5D%7Bx%5E2%2B2x%7D) .
.
So, we can write the given integral as

Splitting up terms and replacing  in the first integral, we get
 in the first integral, we get

 
        
             
        
        
        
Answer:
Step-by-step explanation:
x = 5
x= -4
 
        
                    
             
        
        
        
Answer:
D
Step-by-step explanation:
380 
 
        
             
        
        
        
Answer:
4.575
Step-by-step explanation:
365.085/79.8=4.575