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Softa [21]
3 years ago
3

A tuba creates a 4th harmonic of frequency 116.5 Hz. When the first valve is pushed, it opens an extra bit of tubing 0.721 m lon

g. What is the new frequency of the 4th harmonic ? (Hint : Find the original length .)
Physics
1 answer:
lions [1.4K]3 years ago
0 0

Answer:

The new frequency is:

f₄ = 93.54 Hz

Explanation:

The data given to us is:

No. of harmonic frequency = 4

f₄ = 116.5 Hz

We know that the harmonic frequency is given by the formula:

fₙ = (n · v)/4L

where

n = no. of harmonic frequency

v = speed of sound

L = Length of rope

Lets find the initial length of rope for 4rth harmonic frequency (n=4) and v=343 m/s

fₙ = (n · v)/4L

f₄ = 4v/4L

f₄ = v/L

L = v/f₄

L = 343/116.5

L= 2.944m

Find frequency for new length that is 2.944m + 0.721m = 3.667m

f₄ = v/l

f₄ = 343/3.667

f₄ = 93.54 Hz

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3 0
4 years ago
If a speeding train hits the brakes and it takes the train 39 seconds to go from 54.8 m/s to 12 m/s what is the acceleration?
jekas [21]

Answer:

-1.09m/sec^2

Explanation:

Acceleration= (Vf-Vi)/Time

=12-54.8

= -42.8

= -42.8/39

=-1.09

-ve sign is due to recoil of train

as it suddenly hits brakes.

8 0
3 years ago
Read 2 more answers
What do miles, kilometers, and light-years have in common?<br><br>​
Radda [10]

They are all units of measure of length

Explanation:

Length is a scalar quantity representing a distance between two points, and it can be expressed in different units.

The SI units of the length is the metre (m), which is defined as the length of the path travelled by light in vacuum during a time interval of 1/299,792,458 of a second.

A unit which is common used is a multiple of the meter, the kilometre (km) which corresponds to 1000 metres:

1 km = 1000 m

Another unit used in the UK system is the mile (mi), where the conversion factor between miles and metres is

1 mi = 1609.34 m

Finally, these units are not suitable to be used to measure astronomical distances - such as those between stars and galaxies. For this, another unit is used, which is the light-year (ly), which corresponds to the distance travelled by the light in a vacuum in one year, and its conversion factor to the metre is:

1 ly = 9.46\cdot 10^{15}ly

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6 0
3 years ago
Two trains approach each other on parallel tracks. Each has a speed of 95 kph relative to the ground. If they are initially 8.5
aliya0001 [1]

Answer: 2.83 minutes

Explanation:

It is understood that trains are approaching. That is, they have speeds of equal magnitude but opposite. When train A travels x meters northbound, then train B travels the same distance southbound.

Therefore trains approach at a speed of:

V = 95 +95 = 190\ km / h

Then:

V = \frac{x}{t}\\\\t = \frac{x}{V}

Where x is the distance between the trains

x = 8.5\ km

So the time in which both trains meet is:

t =\frac{8.5\ km}{180\ \frac{km}{h}}\\\\t=0.04722\ hours

This is:

0.04722*\frac{60\ minutes}{1\ hour} = 2.83\ minutes

<em />

<em>How long will it be before they reach one another ?</em>

<h3>2.83 minutes</h3>
3 0
3 years ago
If a net horizontal force of 7.5 N is applied to a baby carriage whose mass is 12.5 kg what acceleration is
11111nata11111 [884]

Answer:

<h2>0.6 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m} \\

f is the force

m is the mass

From the question we have

a =  \frac{7.5}{12.5}  \\

We have the final answer as

<h3>0.6 m/s²</h3>

Hope this helps you

8 0
3 years ago
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