Answer:
A. Passive Transport is migration of a molecule from one side of the cell membrane to the other, from an area of high electrochemical potential to a region of lower electrochemical potential.
B. Diffusion is an individual molecule of a material moving from a high-concentration location to a low-concentration area over a semipermeable barrier
C. Osmosis is the movement of molecules of water through a cell's partly permeable membrane from a liquid with a large concentration of water molecules to a solution with a lower concentration of water molecules.
D. Facilitated Diffusion are molecules that diffuse across the plasma membrane with assistance from membrane proteins, such as channels and carriers.
E. Active transport is the transport of molecules across a cell membrane against a concentration gradient from a low-concentration region to a high-concentration region.
F. Selectively permeable is when some chemicals or ions pass across the membrane, while others are blocked.
G. Cellular respiration are organisms mix oxygen with food molecules, directing the chemical energy in these substances into life-sustaining processes while eliminating carbon dioxide and water as waste material.
Explanation:
Answer:
b. Bakelite
Explanation:
Bakelite -
Bakelite is a form if plastic , and is the very first plastic synthesized .
The handles of the cooking utensils are used to hold the utensil firmly , and hence need not turn hot while cooking , and need to be strong enough to take care of the food .
Hence , the handle should be of the material which is poor conductor of heat and strong .
Hence , bakelite is used for making the handle.
Answer:
B
Explanation:
u do the math and you will get the answer
1. The reactivity among the alkali metals increases as you go down the group due to the decrease in the effective nuclear charge from the increased shielding by the greater number of electrons. The greater the atomic number, the weaker the hold on the valence electron the nucleus has, and the more easily the element can lose the electron. Conversely, the lower the atomic number, the greater pull the nucleus has on the valence electron, and the less readily would the element be able to lose the electron (relatively speaking). Thus, in the first set comprising group I elements, sodium (Na) would be the least likely to lose its valence electron (and, for that matter, its core electrons).
2. The elements in this set are the group II alkaline earth metals, and they follow the same trend as the alkali metals. Of the elements here, beryllium (Be) would have the highest effective nuclear charge, and so it would be the least likely to lose its valence electrons. In fact, beryllium has a tendency not to lose (or gain) electrons, i.e., ionize, at all; it is unique among its congeners in that it tends to form covalent bonds.
3. While the alkali and alkaline earth metals would lose electrons to attain a noble gas configuration, the group VIIA halogens, as we have here, would need to gain a valence electron for an full octet. The trends in the group I and II elements are turned on their head for the halogens: The smaller the atomic number, the less shielding, and so the greater the pull by the nucleus to gain a valence electron. And as the atomic number increases (such as when you go down the group), the more shielding there is, the weaker the effective nuclear charge, and the lesser the tendency to gain a valence electron. Bromine (Br) has the largest atomic number among the halogens in this set, so an electron would feel the smallest pull from a bromine atom; bromine would thus be the least likely here to gain a valence electron.
4. The pattern for the elements in this set (the group VI chalcogens) generally follows that of the halogens. The greater the atomic number, the weaker the pull of the nucleus, and so the lesser the tendency to gain electrons. Tellurium (Te) has the highest atomic number among the elements in the set, and so it would be the least likely to gain electrons.
