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Archy [21]
3 years ago
7

compare (a) the numer of atoms and (b) the number of grams present in 1.00 mole of helium and 1.00 mole of argon

Chemistry
1 answer:
WITCHER [35]3 years ago
8 0

<u>Answer:</u>

For a: The number of atoms of both the gases remains the same.

For b: The number of grams of 1 mole of argon is more than 1 mole of helium by 35.95 grams.

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the number of atoms, we use mole concept.

According to mole concept:

1 mole of an element contains 6.022\times 10^{23} number of atoms.  

We are given two gases of same number of moles.

Therefore, 1 mole of helium gas will contain 1\times 6.022\times 10^{23}=6.022\times 10^{23} number of atoms.

and, 1 mole of argon gas will contain 1\times 6.022\times 10^{23}=6.022\times 10^{23} number of atoms.

Hence, number of atoms of both the given gases remains the same.

  • <u>For 2:</u>

As, the molar mass of both the gases are different, so their masses in 1 mole will be different.

To calculate the number of moles, we use the equation:

\text{Number of Moles}=\frac{\text{Given mass}}{\text{Molar mass}}

  • Calculating the mass of Helium in 1 mole:

Molar mass of helium = 4 g/mol

Putting the values in above equation, we get:  

1mol=\frac{\text{Given mass}}{4g/mol}=4grams

  • Calculating the mass of Argon in 1 mole:

Molar mass of Argon = 39.95 g/mol

Putting the values in above equation, we get:  

1mol=\frac{\text{Given mass}}{39.95g/mol}=39.954grams

Calculating the difference of masses of both the gases = (39.95 - 4)g = 35.95g

Therefore, the mass of argon is more than mass of helium by 35.95 grams.

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C12H26O + SO3+NaOH ----&gt; C12H25NaSO4+ H2O
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Answer:

We can solve this by the method of which i solved your one question earlier

so again here molar mass of C12H25NaSO4 is 288.372 and number of moles for 11900 gm of C12H25NaSO4 will be = 11900/288.372

which is almost = 41.26 moles

so to get one mole of C12H25NaSO4 we need one mole of C12H26O

so for 41.26 moles of C12H25NaSO4 it will require 41 26 moles of C12H26O

so the mass of C12H26O = 41.26× its molar mass

C12H26O = 41.26×186.34

= 7688.38 gm!!

so the conclusion is If you need 11900 g of C12H25NaSO4 (Sodium Lauryl Sulfate) you need C12H26O 7688.38 gm !!

Again i d k wether it's right or wrong but i tried my best hope it helped you!!

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