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oksano4ka [1.4K]
3 years ago
8

Your cell phone bill is $35 a month and $0.05 cents per text message. What is the linear equation, in slope-intercept form, that

represents your bill for one month?
y = 35x - 0.05


y = 35x + 0.05


y = 0.05x - 35


y = 0.05x + 35
Mathematics
1 answer:
Phantasy [73]3 years ago
3 0

Answer:

y=35x+0.05

Step-by-step explanation:

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You have 64 coins, consisting of pennies, nickels, and quarters. The value of
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Answer:

There are 20 pennies, 33 nickels and 11 quarters

Step-by-step explanation:

- You have 64 coins, consisting of pennies, nickels, and quarters

- The value of  the coins is $4.60

- Assume that there are p pennies, n nickles, and q quarters

∴ p + n + q = 64 ⇒ (1)

- Lets find the value of each types of coins

∵ 1 penny = 1 cent ⇒ p = p cents

∵ 1 nickel = 5 cents ⇒ n = 5n cents

∵ 1 quarter = 25 cents ⇒ q = 25q cents

∵ 1 dollar = 100 cents ⇒ $4.60 = 4.60 × 100 = 460 cents

∴ p + 5n + 25q = 460 ⇒ (2)

- You also know that you have three times as many nickels as  quarters

∴ n = 3q ⇒ (3) ⇒ the number of nickles by quarters

∵ 5n = 5(3q)

∴ 5n = 15q ⇒ (4) ⇒ the values of nickles by quarters

- Substitute (3) in equation (1) and (4) in equation (2)

∴ p + 3q + q = 64

∴ p + 4q = 64 ⇒ (5)

∴ p + 15q + 25q = 460

∴ p + 40q = 460 ⇒ (6)

- Subtract equation (5) from equation(6) to eliminate p

∴ 36q = 396

- Divide both sides by 36

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- Substitute the value of q in equation (5)

∴ p + 4(11) = 64

∴ p + 44 = 64

- Subtract 44 from both sides

∴ p = 20

- Substitute the value of q in (3)

∴ n = 3(11) = 33

∴ n = 33

<em>There are 20 pennies, 33 nickels and 11 quarters</em>

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Tessa had $90 in her checking account. She paid her cable/internet bill for $60. She deposited $50 from her part-time job before
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Answer:

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hope this helps!

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Determine algebraically whether f(x)=3x-2 and g(x)=(x+2)/3 are inverse functions. Show all work.
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Answer:

Yes

Step-by-step explanation:

f(x)=3 x-2      

     

y= 3 x-2      

             

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<u>3 y </u> =  <u>x  </u> +  <u>2</u>                                                      

3        3       3

<u>3 y </u> =  <u>x  </u> +  <u>2  </u>                                                    

3        3       3

y =  <u>x </u>  +  <u>2   </u>        replace y with f ^ -1(x)

   <em> </em>  3        3                                            

f ^-1 (x) =    <u>x</u>   +  <u>2 </u>        

                 3       3      

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