Question

How many free electrons are there in 2.55 cm^ ^ 3 of pure Silicon Note N = Vp and rho = 1.54 free electrons / cm ^3

Answer 1

Answer:

C: 3.93 x 10^22 free electrons

Explanation:

The no. of free electrons can be found out using the following formula:

$N = V\rho$

where,

N = No. of free electrons = ?

V = Volume = 2.55 cm³

ρ = density of electrons = 1.54 x 10²² free electrons/cm³

Therefore, using these values in the equation, we get:

$N = (2.55\ cm^3)(1.54\ x\ 10^{22}\ free\ electrons/cm^3)$

N = 3.93 x 10²² free electrons

Therefore, the correct option is:

C: 3.93 x 10^22 free electrons