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tamaranim1 [39]
3 years ago
13

5. Write the two resonance hybrids for the carbocation that would be formed by protonation at C-1 of 2-methyl-1,3-pentadiene. Wi

thout doing a calculation, would you expect C-2 or C-4 (the two end carbons of the allylic cation) to have the most positive charge on it
Chemistry
1 answer:
kupik [55]3 years ago
7 0

Answer:

Follows are the solution to this question:

Explanation:

Please find the complete solution in the attached file.

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Chemical equations must be balanced to satisfy ...?
murzikaleks [220]

Answer:

the law of conservation of matter.

Explanation:

I am in chem

4 0
3 years ago
Read 2 more answers
Use the drop-down menus to classify each of the following as an addition, substitution, elimination, or
OLga [1]

Answer:

CH3CHO+H2O → CH3OCH3 - addition

CH,CICH CI + Zn → C2H4 + ZnCl2 - elimination

CH3CH3Br + OH – CH3CH3OH + Br - substitution

2CH2COOH >>(CH3CO)20 + H20 - condensation

Explanation:

An addition reaction is a reaction in which a specie is added across the double bond as we can see in CH3CHO+H2O → CH3OCH3.

In an elimination reaction, a small molecule is lost from a saturated compound to form the corresponding unsaturated compound as in CH,CICH CI + Zn → C2H4 + ZnCl2

In a substitution reaction, a chemical moiety replaces another in a molecule as in; CH3CH3Br + OH – CH3CH3OH + Br .

A condensation reaction is in which two molecules are joined together to form a bigger molecule as in; 2CH2COOH >>(CH3CO)20 + H20.

4 0
3 years ago
Help me please???????
AlexFokin [52]

Answer:

geez I have no clue sorry

6 0
3 years ago
If 100.0 grams of na3n decompose to form sodium and nitrogen, how many moles of sodium are formed? write and balance equation be
Yakvenalex [24]
The balanced equation is:
2Na_3N-\ \textgreater \ 6Na + N_2

Then proceed with the following equations.


100g Na_3N*(\frac{1molNa_3N}{82.98gNa_3N})*(\frac {6mol Na}{2molNa_3N})*(\frac {22.99gNa}{1molNa})=83.12gNa

The answer is 83.12gNa.
7 0
3 years ago
Read 2 more answers
If it requires 75.0mL of 0.500M NaOH to neutralize 165.0 mL of an hcl solution what is the concentration of the hcl solution
Kaylis [27]

Answer:

0.027 M HCl

Explanation:

The chemical equation of the neutralization is:

1 NaOH + 1 HCl -> 1 H2O + 1 NaCl

Because the ratio of NaOH and HCl is 1:1 you can use the M1V1=M2V2 formula.

(75 mL)(0.5 M NaOH) = (165 mL)(M HCl)

It requires 0.027 M HCl.

7 0
3 years ago
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