Answer: The final volume of this solution is 0.204 L.
Explanation:
Given: Molarity of solution = 2.2 M
Moles of solute = 0.45 mol
Molarity is the number of moles of solute present divided by volume in liters.
Substitute the values into above formula as follows.
Thus, we can conclude that the final volume of this solution is 0.204 L.
Mixture/ compound
hope this helps
There should be mass balance and the charge balance between the reactants and the products
Mass balance : total no of individual atoms of each type should be balanced before and after the reaction
Charge balance : Overall charge of the reactants should be balanced with the overall charge of the products
You can balance,
1)by just looking at it
2)by Algebraic method given above or
3)by the redox method
You need to know how to get the oxidation numbers in order to use the oxidation method
This is an acid – base reaction and this always result a salt and water
in a neutralization reaction. <span>
The salt that is formed will be calcium bromide (calcium
is located in group 2 so calcium bromide has a formula of CaBr2)
so essentially we got:
HBr + Ca(OH)2 ------> CaBr2 + H2O </span>
balancing the elements: <span>
<span>2HBr(aq) + Ca(OH)2(aq) --------> CaBr2(aq) +
2H2O(l)</span></span>
Answer:
- 6.38x10²² molecules C₆H₁₂O₆
Explanation:
First we <u>convert the given masses into moles</u>, using the <em>compounds' respective molar mass</em>:
- 64.7 g N₂ ÷ 28 g/mol = 2.31 mol N₂
- 83 g CCl₄ ÷ 153.82 g/mol = 0.540 mol CCl₄
- 19 g C₆H₁₂O₆ ÷ 180 g/mol = 0.106 mol C₆H₁₂O₆
Then we multiply each amount by <em>Avogadro's number</em>, to <u>calculate the number of molecules</u>:
- 2.31 mol N₂ * 6.023x10²³ molecules/mol = 1.39x10²⁴ molecules
- 0.540 mol CCl₄ * 6.023x10²³ molecules/mol = 3.25x10²³ molecules
- 0.106 mol C₆H₁₂O₆ * 6.023x10²³ molecules/mol = 6.38x10²² molecules
