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3 years ago

What are some forms of mechanical energy

1 answer:

4 0

Objects have mechanical energy<span> if they are in motion and/or if they are at </span>some<span> position relative to a zero potential </span>energy<span> position (for example, a brick held at a vertical position above the ground or zero height position). A moving car possesses </span>mechanical energy<span> due to its motion (kinetic </span>energy<span>).</span>

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An object has an acceleration of 12.0 m/s/s. The mass of the object is doubled while the net force on the object is held constan

Aloiza [94]

Answer:

The net force acting on the object is doubled while the mass of the object is held constant. What will be the new acceleration? An object has an acceleration of 12.0 m/s^2. The net force acting on the object is halved (decreased to one half its original value) while the mass of the object is held constant.

7 0

3 years ago

The human eye can readily detect wavelengths from about 400 nm to 700 nm. part a if white light illuminates a diffraction gratin

Lera25 [3.4K]

We are given that the wavelength ʎ is from 400 nm to 700 nm. The formula for this is:

d sin a =m * ʎ

where,

d = slit separation = 1 mm / 750 lines = 1/750

a = angle

m = 1

ʎ = 400 nm to 700 nm = 0.0004 mm to 0.0007 mm

Rewriting the formula in terms of angle a:

a = sin^-1 (m ʎ / d)

when ʎ = 0.0004 mm

a = sin^-1 (0.0004 / (1/750))

a = 17.46°

when ʎ = 0.0007 mm

a = sin^-1 (0.0007 / (1/750))

a = 31.67°

Hence the range of angles is from 17.46° to 31.67<span>°.</span>

3 0

3 years ago

What happen when a star dies?

Vera_Pavlovna [14]

It depends on the size of the star. If it's size was normal then it cools down into White dwarf, then a black dwarf. If a really huge star dies, then we can see a "Supernova" from that.

Hope this helps!!

7 0

3 years ago

The pressure inside a sealed container of methane gas (CH4) is 35.0 kPa. If this 80.0 L sample

STatiana [176]

Answer:

<h3>The answer is 30.43 L</h3>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the new volume

$V_2 = \frac{P_1V_1}{P_2} \\$

From the question we have

$V_2 = \frac{35000 \times 80}{92000} = \frac{2800000}{92000} = \frac{700}{23} \\ = 30.434782...$

We have the final answer as

Hope this helps you

4 0

3 years ago

A sound is recorded at 19 decibels. What is the intensity of the sound?

sp2606 [1]

$1 \times 10^{-10.1} \mathrm{Wm}^{-2}$ is the intensity of the sound.

Answer: Option B

<u>Explanation:</u>

The range of sound intensity that people can recognize is so large (including 13 magnitude levels). The intensity of the weakest audible noise is called the hearing threshold. (intensity about $1 \times 10^{-12} \mathrm{Wm}^{-2}$ ). Because it is difficult to imagine numbers in such a large range, it is advisable to use a scale from 0 to 100.

This is the goal of the decibel scale (dB). Because logarithm has the property of recording a large number and returning a small number, the dB scale is based on a logarithmic scale. The scale is defined so that the hearing threshold has intensity level of sound as 0.

$\text { Intensity }(d B)=(10 d B) \times \log _{10}\left(\frac{I}{I_{0}}\right)$

Where,

I = Intensity of the sound produced

$I_{0}$ = Standard Intensity of sound of 60 decibels = $1 \times 10^{-12} \mathrm{Wm}^{-2}$

So for 19 decibels, determine I as follows,

$19 d B=(10 d B) \times \log _{10}\left(\frac{I}{1 \times 10^{-12} W m^{-2}}\right)$

$\log _{10}\left(\frac{1}{1 \times 10^{-12} \mathrm{Wm}^{-2}}\right)=\frac{19}{10}$

$\log _{10}\left(\frac{1}{1 \times 10^{-12} \mathrm{Wm}^{-2}}\right)=1.9$

When log goes to other side, express in 10 to the power of that side value,

$\left(\frac{I}{1 \times 10^{-12} W m^{-2}}\right)=10^{1.9}$

$I=1 \times 10^{-12} \mathrm{Wm}^{-2} \times 10^{1.9}=1 \times 10^{-12-1.9}=1 \times 10^{-10.1} \mathrm{Wm}^{-2}$

5 0

3 years ago