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3 years ago

What are some forms of mechanical energy

1 answer:

4 0

Objects have mechanical energy if they are in motion and/or if they are at some position relative to a zero potential energy position (for example, a brick held at a vertical position above the ground or zero height position). A moving car possesses mechanical energy due to its motion (kinetic energy).

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vector a having mignitude 3.2 makes 50degre with x-axis and vector b with magnitude 5.2 makes 110degre with x-axis what is the m

Svetllana [295]

Yep ask google good idea

8 0

3 years ago

A dentist’s drill starts from rest. After 3.20 s of constant angu-lar acceleration, it turns at a rate of 2.51 3 104 re v/m i n.

Gekata [30.6K]

Answer:

$ΔTita = 4205.6 rad$

Explanation:

$w_{i}$ means initial angular velocity, which is 0 rev/min

$w_{f}$ means final angular velocity, which is $2.513*10^{4}rev/min$

t means time t= 3.20 s

one revolution is equivalent to 2πrad so the final angular velocity is:

$w_{f}$ = (2π/60) *2.513*10^{4} rad/s

$w_{f}$ = 2628.5 rad/s

so the angular acceleration, α will be:

α = 2628.5 rad/s / 3.20 s

$a = 821.40 rad/s^{2}$

so the rotational motion about a fixed axis is:

$w^{2} _{f} =w^{2} _{i}$ + 2αΔTita where ΔTita is the angle in radians

so now find the ΔTita the subject of the formula

ΔTita = $\frac{w^{2} _{f}-w^{2} _{i} }{2a}$

$ΔTita = ((2628.5)^{2} - (0 rev/min)^{2}) / 2* 821.40$

$ΔTita = 4205.6 rad$

7 0

4 years ago

Read 2 more answers

Which of the following correctly describes the state of matter of one of the samples?

zheka24 [161]

I think the answer is D

3 0

3 years ago

If the index of refraction of a medium is 1.4, determine the speed of light in that medium.

Damm [24]

The speed of light in that medium is $2.14 \times 10^8 \ m/s$ .

Explanation:

It is known that the light's speed is constant when it travels in vacuum and the value is $3 \times 108 m/s$ . When the light enters another medium other than vacuum, its speed get decreased as the light gets refracted by an angle.

The amount of refraction can be determined by the index of refraction or refractive index of the medium. The refraction index is measured as the ratios of speed of light in vacuum to that in the medium. It is represented as η = $\frac {c}{v}$

So, here η is the index of refraction of a medium which is given as 1.4, c is the light's speed in vacuum ( $3 \times 10^8 ms^-^1$ ) and v is the light's speed in that medium which we need to find.

$1.4= \frac{(3 \times 10 ^ 8)} {v}$

$v= \frac {(3 \times 10^8)}{1.4} =2.14 \times 10^8 \ m/s$

Thus the speed of light in that medium is $2.14 \times 10^8 \ m/s.$

3 0

3 years ago

5. If 100N effort is required to lift a load of 300N in a lever of 1m and distance between fulcrums to load is 30 cm then, calcu

pishuonlain [190]

effort distance =?

effort =100N

load =300N

lever =1m

load D =30cm

ma=?

vr=?

efficiency =?

we know that

effort distance =l ×ld

= 300×30

9000

ma= l ×e

= 100×300

= 30000

vr = ld ×ed

= 1×9000

=9000

efficiency =(ma÷vr)/100

(30000÷9000)×100

3.33×100

333

5 0

3 years ago