What are some forms of mechanical energy
1 answer:
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Answer:
A+B; 5√5 units, 341.57°
A-B; 5√5 units, 198.43°
B-A; 5√5 units, 18.43°
Explanation:
Given A = 5 units
By vector notation and the axis of A, it is represented as -5j
B = 3 × 5 = 15 units
Using the vector notations and the axis, B is +15i. The following vectors ate taking as the coordinates of A and B
(a) A + B = -5j + 15i
A+B = 15i -5j
|A+B| = √(15)²+(5)²
= 5√5 units
∆ = arctan(5/15) = 18.43°
The angle ∆ is generally used in the diagrams
∆= 18.43°
The direction of A+B is 341.57° based in the condition given (see attachment for diagrams
(b) A - B = -5j -15i
A-B = -15i -5j
|A-B|= √(15)²+(-5)²
|A-B| = √125
|A-B| = 5√5 units
The direction is 180+18.43°= 198.43°
See attachment for diagrams
(c) B-A = 15i -( -5j) = 15i + 5j
|B-A| = 5√5 units
The direction is 18.43°
See attachment for diagram
Answer:
The resulting speed of the airplane is 150 Km/h
Explanation:
The airspeed of the plane is 120 Km/h due North. The wind came from West pointing to the East at 90 Km/h
Both speeds are acting in different directions, so they must be added as vectors. Both vectors and the resulting velocity (Vr) are shown in the image below
The magnitude of that velocity can be computed by using Pythagoras's theorem:
The resulting speed of the airplane is 150 Km/h
