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const2013 [10]
2 years ago
11

Why did all sodium compounds show the same colour in the flame? (flame test)

Chemistry
1 answer:
mojhsa [17]2 years ago
5 0

Answer:

Every element has its own particular spectrum of colours that the atoms or ions will emit when energy (in this case heat) is supplied. ... So, the sodium in sodium chloride, sodium nitrate, etc all produce the same bright yellow colour that is a characteristic of sodium.

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A scientist has two samples of gas: The first sample contains one mole of argon atoms and has a mass of 39.948 g; the second sam
V125BC [204]

There are 6.022 × 10²³ atoms in 39.948 g of argon and 4.0026 g of helium.

Explanation:

39.945 g/mole is the molar mass of argon so 39.948 g of argon are equal to 1 mole of argon.

4.0026 g/mole is the molar mass of helium so 4.0026 g of helium are equal to 1 mole of helium.

We know that Avogadro's number tell us the number of particles in 1 mole of substance which is 6.022 × 10²³.

So in 39.948 g of argon and 4.0026 g of helium contains the same number of atoms, 6.022 × 10²³.

Learn more about:

Avogadro's number

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4 0
3 years ago
clasificar cada una de ellas en alcohol, cetona, acido carboxílico, benceno, amida... acetaminofen, testosterona, acido citrico​
ASHA 777 [7]

Answer:

saiffjyrkieijdyc digit both of dvur is the answer rcjcufi

7 0
3 years ago
Which of the following is the correct name for the compound S3Cl2? Sulfur chloride Sulfur (III) chloride Sulfur (II) chloride Tr
Rus_ich [418]
Sulfur is not a transition metal so it does not need a Roman numeral the correct answer is Trisulfur Dichloride
8 0
3 years ago
Read 2 more answers
State where the chemical potential energy released from a reaction is stored
Vlad [161]
It is stored in the bonds between atoms.
4 0
3 years ago
opper(I) ions in aqueous solution react with NH 3 ( aq ) according to Cu + ( aq ) + 2 NH 3 ( aq ) ⟶ Cu ( NH 3 ) + 2 ( aq ) K f =
Y_Kistochka [10]

Answer:

55.373g/l

Explanation:

The dissolved amount of sparingly soluble salts is interlinked with a unitlesss quantity called as solubility product. It is a fixed quantity that only increases with the rise in temperatures and is used to predict the salting out of compounds. If the value of ionic product (Q) is larger than (Ksp), precipitation of compound occurs.

Given:

The solubility product of CuBr is 6.3×10−9.

The concentration of NH3 is 0.10 M.

Formula and Calculations:

The dissolution reaction (I) of CuBr is shown below.

The reaction showing dissolution of CuBr in NH3 is shown below.

The above reaction can be obtained by adding reaction (I) and (II) as shown below.

The equilibrium constants will get multiplied.

Suppose the solubility of CuBr is “s”.

It is given that concentration of NH3 is 0.10 M.

The equilibrium constant expression for the above reaction is as follows,

Here,

The concentration of pure solids is 1 M. Thus, the concentration of CuBr is 1 M.

As calculated, the value of Ksp is 396.9.

Substitute all the required values in above formula.  

On further solving above equation,

Therefore, the solubility of CuBr in ammonia is 0.386 M.

The formula to calculate solubility

Solubuility (g/l)= Molarity(M) x Molarmass

Chemistry homework question answer, step 2, image 10

The molar mass of CuBr is 143.45 g/mol.

The formula to calculate solubility in g/L is given below.

The molar mass of CuBr is 143.45 g/mol.

therefore,

solubility = 0.386M x 143.45g/mol

where (M = mol/l)

solubility = 55.375g/l

5 0
3 years ago
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