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2 years ago

Why did all sodium compounds show the same colour in the flame? (flame test)

Chemistry

1 answer:

mojhsa [17]2 years ago

5 0

Answer:

Every element has its own particular spectrum of colours that the atoms or ions will emit when energy (in this case heat) is supplied. ... So, the sodium in sodium chloride, sodium nitrate, etc all produce the same bright yellow colour that is a characteristic of sodium.

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May someone help me on this

Kamila [148]

Answer:

<h2>The mosquitoes like when its wet and moist than dry temp.</h2>

7 0

2 years ago

Solve this word problem:

valina [46]

Answer:

The new acceleration becomes twice the pervious acceleration.

Explanation:

Given that,

Mass of the rock, m = 3 kg

Force, F = 1 N

We know that the force acting on an object is given by :

F = ma

a is acceleration of the rock

Put m = 3 kg and F = 1N,

$a=\dfrac{F}{m}\\\\a=\dfrac{1}{3}\ m/s^2$

If the force is doubled, F' = 2 N

So,

F'=ma'

$a'=\dfrac{F'}{m}\\\\a'=\dfrac{2\times 1}{3}\\\\a'=\dfrac{2}{3}\\\\a'=2\times \dfrac{1}{3}\\\\a'=2a$

So, the new acceleration becomes twice the initial acceleration.

3 0

3 years ago

Can you make the particles of any of the substances stop moving?

ser-zykov [4K]

The particles cannot move around at all. The particles are, however, still in motion.

3 0

3 years ago

"determine the mass of oxygen" in a 7.9 g sample of al2(so4)3.

jeyben [28]

Answer:

4.43 g of Oxygen

Explanation:

As shown in Chemical Formula, one mole of Aluminium Sulfate [Al₂(SO₄)₃] contains;

2 Moles of Aluminium

3 Moles of Sulfur

12 Moles of Oxygen

Also, the Molar Mass of Aluminium Sulfate is 342.15 g/mol. It means,

342.15 g ( 1 mole) of Al₂(SO₄)₃ contains = 192 g (12 mole) of O

So,

7.9 g of Al₂(SO₄)₃ will contain = X g of O

Solving for X,

X = (7.9 g × 192 g) ÷ 342.15 g

X = 4.43 g of Oxygen

7 0

2 years ago

In the reaction BaCO3 + 2HNO3 + Ba(NO3)2 + CO2 + H2O, what mass of Ba(NO3)2 can be formed by combining 55 g BaCO3 and 26 g HNO3

Nataliya [291]

From the stoichiometry of the reaction, the mass of barium nitrate produced is 54.9 g.

<h3>Stoichiometry</h3>

The term stoichiometry refers to mass - volume relationships. Stoichiometry can be used to calculate the amount, mass or volume of reactants and products from the balanced reaction equation.

The equation of the reaction is written as follows;

BaCO3 + 2HNO3 ------> Ba(NO3)2 + CO2 + H2O

Number of moles of BaCO3 = 55 g/197.34 g/mol = 0.28 moles

Number of moles of HNO3 = 26 g/63.01 g/mol = 0.41 moles

From the reaction equation;

1 mole of BaCO3 reacts with 2 moles of HNO3

0.28 moles of BaCO3 reacts with 0.28 moles × 2 moles/1 mole = 0.56 moles

There is not enough HNO3 hence it is the limiting reactant.

Number of moles of Ba(NO3)2 produced is obtained from;

2 moles of HNO3 yields 1 mole of Ba(NO3)2

0.41 moles of HNO3 yields 0.41 moles × 1 mole/2 moles

= 0.21 moles of Ba(NO3)2

Mass of Ba(NO3)2 = 0.21 moles × 261.337 g/mol = 54.9 g

Learn more about stoichiometry: brainly.com/question/9743981

8 0

2 years ago