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alex41 [277]
3 years ago
12

2001240Determine the specific kinetic energy of a mass whose velocity is 40 m/s, in kJ/kg.

Physics
1 answer:
guapka [62]3 years ago
6 0

Answer:

The specific kinetic energy of a mass is 0.8 kJ/kg

Explanation:

Given that,

Velocity = 40 m/s

Specific kinetic energy is the kinetic energy per unit mass.

We need to calculate the specific kinetic energy

Using formula of specific kinetic energy

K.E=\dfrac{\dfrac{1}{2}mv^2}{m}

K.E=\dfrac{v^2}{2}

Put the value into the formula

K.E=\dfrac{40^2}{2}

K.E=800\ J/kg

We know that,

1 kJ = 1000 J

or, 1J=0.001 KJ

The specific energy is

K.E=800\times0.001

K.E=0.8\ kJ/kg

Hence, The specific kinetic energy of a mass is 0.8 kJ/kg

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What is the independent variable and dependent variable if the question is How much weight can you add to a boat before it sinks
Serhud [2]

The independent variable is how much weight you add to the boat.

The dependent variable is: Did it or did it not sink yet ?


6 0
3 years ago
A caregiver's love, affection, and acceptance are considered conditional if they're given only when the child is well-behaved or
murzikaleks [220]

Hello there!  Yes, this is a TRUE statement.

Conditional means something happens on the condition of something else happening. In this case, the something else happening is if the child "child is well-behaved or meets set expectations", and the thing happening because of this is the caregiver's " love, affection, and acceptance". If the child was not any of the things listed, the caregiver would not be the things listed.

I hope this helps, have a great day! :)

4 0
3 years ago
Read 2 more answers
Runner A is initially 5.7 km west of a flagpole and is running with a constant velocity of 8.9 km/h due east. Runner B is initia
Oksanka [162]

Answer:

B meet A 0.01 km east of flagpole

Explanation:

given data

distance A = 5.7 km  west

velocity V1 = 8.9 km/h

distance B = 4.5 km  east

velocity V2 = 7 km/h

to find out

How far runners from the flagpole, when paths cross

solution

we know A and B are 5.7 + 4.5 = 10.2 km apart

and we consider here B will run distance x km for meet

so time will be for B is

time B = distance / velocity

time B = x / 7     ...................1

and

for A distance for meet = ( 10.2 - x ) km

so time A = distance / velocity

time A = ( 10.2 - x )  / 8.9      .............2

now equating equation 1 and 2

time A = time B

x / 7  =   ( 10.2 - x )  / 8.9

x = 4.490

so distance of B run for meet is 4.490 km

so distance from the flagpole when their paths cross is 4.5 - 4.490 = 0.01 km

so B meet A 0.01 km east of flagpole

4 0
3 years ago
The same ball is shot straight up a second time from the same gun, but this time the spring is compressed only half as far befor
Mekhanik [1.2K]

Answer:

The new height the ball will reach = (1/4) of the initial height it reached.

Explanation:

The energy stored in any spring material is given as (1/2)kx²

This energy is converted to potential energy, mgH, of the ball at its maximum height.

If the initial height reached is H

And the initial compression of the spring = x

So, mgH = (1/2)kx²

H = kx²/2mg

The new compression, x₁ = x/2

New energy of loaded spring = (1/2)kx₁²

And the new potential energy = mgH₁

mgH₁ = (1/2)kx₁²

But x₁ = x/2

mgH₁ = (1/2)k(x/2)² = kx²/8

H₁ = kx²/8mg = H/4 (provided all the other parameters stay constant)

6 0
3 years ago
What are the 3 basic parts of an atom and what are their charges?
kotegsom [21]

Answer:

electrons neutrons and protons

Explanation:

electron are negative

nuetron are neutral

protons are positive

7 0
3 years ago
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