Answer:
0.624 kg
Explanation:
We are given that
Mass of one block,
We have to find the mass of second block.
Mass of second block,
Substitute the values
Hence, the mass of second block=0.624Kg
Answer:
Given gravity 9. A simple pendulum on Earth has a period of 6.0 seconds. What would the period of this pendulum be on Jupiter, if the acceleration of gravity on the surface of Jupiter is 26 m/s2 i know that 6.0s=2pi * (L/9.8) <-since that is the gravity on earth
Explanation:
Answer:
t = 22.2 s
Explanation:
angular distance covered in the 36.0 s is
θ = ω(avg)t = ½(10.0 + 30.0)36 = 720 radians
720/2 = 360 radians
α = Δω/t = (30 - 10)/36 = 5/9 rad/s²
θ = ω₀t + ½αt²
360 = 10.0t + ½(5/9)t²
0 = (5/18)t² + 10.0t - 360
0 = t² + 36t - 1296
t = (-36 ±√(36² - 4(1)(-1296))) / 2
t = (-36 ±√(6480)) / 2
t = -18 ±√1620
we ignore the negative time result as it occurs before we care.
t = -18 + √1620 = 22.249223... s
Answer:
false
Explanation:
the planet saturn rotates around the sun at 21,637mph
the planet mars rotates around the sun at 53,979mph
half the speed of mars is 26,989.5mph
Answer:
The distance is
Explanation:
From the question we are told that
The smallest shift is
Generally a grid unit is of an arcsec
This implies that 0.2 grid unit is
The maximum distance at which a star can be located and still have a measurable parallax is mathematically represented as
substituting values
Note
So