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BartSMP [9]
3 years ago
7

Which of the following is not the same as 12.5 millimeters? 0.0000125 km 0.00125 hm 0.0125 m 1.25 cm

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
5 0
1 mm (millimeter) = 0.000001 km (kilometer)
12.5 mm = <span>0.0000125 km

1 mm = </span><span>0.00001 hm (hectometer)
12.5 mm = </span><span>0.000125 hm

1 mm = </span>0.001 m (meter)
12.5 mm = 0.0125 m

1 mm = 0.1 cm (centimeter)
12.5 mm = 1.25 cm

So the only one of the answer choices that doesn't equal 12.5 mm is 0.00125 hm, since 12.5 mm is <span>0.000125 hm.

Answer:
</span><span>0.00125 hm
</span><span>
Hope this helps!</span>
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Answer:

The pressure of the gas at 23 C is 179.92 kPa.

Explanation:

Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.

Gay-Lussac's law can be expressed mathematically as follows:

\frac{P}{T} =k

Studying two states, one initial 1 and the other final 2, it is satisfied:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 310 kPa
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  • P2= ?
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Replacing:

\frac{310 kPa}{510 K} =\frac{P2}{296 K}

Solving:

P2=296 K*\frac{310 kPa}{510 K}

P2= 179.92 kPa

<u><em>The pressure of the gas at 23 C is 179.92 kPa.</em></u>

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<em><u>we </u></em><em><u>need </u></em><em><u>to </u></em><em><u> </u></em><em><u>put</u></em>

<em><u>Ag2O</u></em><em><u>. </u></em><em><u>=</u></em><em><u> </u></em><em><u> </u></em><em><u>2</u></em><em><u> </u></em>

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