1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vladimir79 [104]
2 years ago
6

Sulfuric acid is produced in larger amounts by weight than any other chemical. It is used in manufacturing fertilizers, oil refi

ning, and hundreds of other processes. An intermediate step in the industrial process for the synthesis of H2SO4 is the catalytic oxidation of sulfur dioxide: 2SO2(g)+O2(g)→2SO3(g)ΔG∘ = -141.8 kJ Calculate ΔG at 25 ∘C given the following sets of partial pressures.Part A
130atm SO2, 130atm O2, 2.0atm SO3
Express your answer using four significant figures.
Part B
5.0atm SO2, 3.0atm O2, 30atm SO3
Express your answer using four significant figures.
Part CEach reactant and product at a partial pressure of 1.0 atm.
Express your answer using four significant figures.
Chemistry
1 answer:
Fed [463]2 years ago
7 0

Answer:

A. -166.6 kJ/mol

B. -127.7 kJ/mol

C. -133.9 kJ/mol

Explanation:

Let's consider the oxidation of sulfur dioxide.

2 SO₂(g) + O₂(g) → 2 SO₃(g)     ΔG° = -141.8 kJ

The Gibbs free energy (ΔG) can be calculated using the following expression:

ΔG = ΔG° + R.T.lnQ

where,

ΔG° is the standard Gibbs free energy

R is the ideal gas constant

T is the absolute temperature (25 + 273.15 = 298.15 K)

Q is the reaction quotient

The molar concentration of each gas ([]) can be calculated from its pressure (P) using the following expression:

[]=\frac{P}{R.T}

<em>Calculate ΔG at 25°C given the following sets of partial pressures.</em>

<em>Part A  130atm SO₂, 130atm O₂, 2.0atm SO₃. Express your answer using four significant figures.</em>

[SO_{2}]=[O_{2}]=\frac{130atm}{(0.08206atm.L/mol.K).298K} =5.32M

[SO_{3}]=\frac{2.0atm}{(0.08206atm.L/mol.K).298K} =0.0818M

Q=\frac{[SO_3]^{2} }{[SO_{2}]^{2}.[O_{2}] } =\frac{0.0818^{2} }{5.32^{3} } =4.44 \times 10^{-5}

ΔG = ΔG° + R.T.lnQ = -141.8 kJ/mol + (8.314 × 10⁻³ kJ/mol.K) × 298 K × ln (4.44 × 10⁻⁵) = -166.6 kJ/mol

<em>Part B  5.0atm SO₂, 3.0atm O₂, 30atm SO₃  Express your answer using four significant figures.</em>

<em />

[SO_{2}]=\frac{5.0atm}{(0.08206atm.L/mol.K).298K}=0.204M

[O_{2}]=\frac{3.0atm}{(0.08206atm.L/mol.K).298K}=0.123M

[SO_{3}]=\frac{30atm}{(0.08206atm.L/mol.K).298K}=1.23M

Q=\frac{[SO_3]^{2} }{[SO_{2}]^{2}.[O_{2}] } =\frac{1.23^{2} }{0.204^{2}.0.123 } =296

ΔG = ΔG° + R.T.lnQ = -141.8 kJ/mol + (8.314 × 10⁻³ kJ/mol.K) × 298 K × ln 296 = -127.7 kJ/mol

<em>Part C Each reactant and product at a partial pressure of 1.0 atm.  Express your answer using four significant figures.</em>

<em />

[SO_{2}]=[O_{2}]=[SO_{3}]=\frac{1.0atm}{(0.08206atm.L/mol.K).298K}=0.0409M

Q=\frac{[SO_3]^{2} }{[SO_{2}]^{2}.[O_{2}] } =\frac{0.0409^{2} }{0.0409^{3}} =24.4

ΔG = ΔG° + R.T.lnQ = -141.8 kJ/mol + (8.314 × 10⁻³ kJ/mol.K) × 298 K × ln 24.4 = -133.9 kJ/mol

You might be interested in
Please help me for real
Bond [772]

Answer:

I believe it is the replication fork. so B

Explanation:

I haven't done this section in quite some time. this was biology for me, and I'm in chem right now. so I hope that's right. I hope I could help you :)

7 0
3 years ago
Pls I need help give away 11 points
Maru [420]

Answer:

The charge is +2

Explanation:

Protons are positive, electrons are negative. 10-8=2.

+2 :)

7 0
3 years ago
A 15.00-ml sample of a naoh solution of unknown concentration requires 17.88 ml of a 0.1053 m h2so4 solution to reach the equiva
Sergeu [11.5K]

Answer:

  • <u>0.1255 M</u>

Explanation:

<u>1) Data:</u>

Base: NaOH

Vb = 15.00 ml = 15.00 / 1,000 liter

Mb = ?

Acid: H₂SO₄

Va = 17.88 ml = 17.88 / 1,000 liter

Ma = 0.1053

<u>2) Chemical reaction:</u>

The <em>titration</em> is an acid-base (neutralization) reaction to yield a salt and water:

  • Acid + Base → Salt + Water

  • H₂SO₄ (aq) + NaOH(aq) → Na₂SO₄ (aq) + H₂O (l)

<u>3) Balanced chemical equation:</u>

  • H₂SO₄ (aq) + 2 NaOH(aq) → Na₂SO₄ (aq) + 2H₂O (l)

Placing coefficient 2 in front of NaOH and H₂O balances the equation

<u>4) Stoichiometric mole ratio:</u>

The coefficients of the balanced chemical equation show that 1 mole of H₂SO₄ react with 2 moles of NaOH. Hence, the mole ratio is:

  • 1 mole H₂SO₄ : 2 mole NaOH

<u>5) Calculations:</u>

a) Molarity formula: M = n / V (in liter)

   ⇒ n = M × V

b) Nunber of moles of acid:

  • nₐ = Ma × Va = 0.1053 (17.88 / 1,000)

c) Number of moles of base, nb:

  • nb = Mb × Vb = Mb × (15.00 / 1,000)

d) At equivalence point number of moles of acid = number of moles of base

  • nₐ = nb

  • 0.1053 × (17.88 / 1,000) =  Mb × (15.00 / 1,000)

  • Mb = 0.1053 × 17.88  / 15.00 = 0.1255 mole/liter = 0.1255 M
3 0
3 years ago
Read 2 more answers
Which is the formula for nitrogen trihydride? NH3 N3H 3NH N3H3
Firlakuza [10]

the answer isssssssssssssssssssssss... Nh3.

7 0
2 years ago
Its gelatin and a fruit cup the same (its for a project)
gizmo_the_mogwai [7]

Answer:

No

Explanation:

Gelatin is a substance that makes jello, and a fruit cup is a cup full of fruit

6 0
2 years ago
Read 2 more answers
Other questions:
  • PLS help it is a timed test!
    6·1 answer
  • PLEAASSEEE Explain, really confused
    6·1 answer
  • Burning magnesium gives us magnesium oxide. This is an example of a reaction.
    14·2 answers
  • Worth 13 points plzzz helpp
    8·2 answers
  • Why must ionic compound have a total charge of 0?
    9·1 answer
  • A chemical reaction done at STP conditions is supposed to produce 0.011 moles of CO2 gas. How many liters of gas will that be?
    5·1 answer
  • When water is added to a mixture Na_2O_2(s) and S(s), a redox reaction occurs, as represented by the equation below.
    14·1 answer
  • Answer the following problem-
    5·1 answer
  • a satellite with a mass of 100kg fires it’s engines to increase velocity, thereby increasing the size of its orbit around the ea
    14·1 answer
  • in the titration of naoh with vinegar, a student forgot to condition the buret, and it was wet with deionized water before filli
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!