Answer:
Explanation:
a) Linear density is greater on the left side because the velocity of wave in a string is inversely proportional to the linear mass density of the string
b) We should start pulse from the left hand side so the reflected wave does not get inverted because the wave traveling from the denser to lighter medium gets reflected in the same phase.
Answer:
16.25 m
Explanation:
we know that the equation pf parabola
![y=kx^2](https://tex.z-dn.net/?f=y%3Dkx%5E2)
from bellow figure the coordinate of parabola is (600,65) that is y=600 and x=65
putting the the value of y and x in the equation of parabola
![65=k600^2](https://tex.z-dn.net/?f=65%3Dk600%5E2)
k=0.0001805
now the equation is
![y=0.0001805x^2](https://tex.z-dn.net/?f=y%3D0.0001805x%5E2)
we have to find the value of y at x=300m
so ![y=0.0001805\times 300^2](https://tex.z-dn.net/?f=y%3D0.0001805%5Ctimes%20300%5E2)
y=16.25 m
Answer:
the car you are in the cars have the same time frame and one covers more ground so on a possition time graph the slope will be greater
Answer:
m₂ = 18 kg
Explanation:
Conceptual analysis
We apply Newton's second law on masses m₁ and m₂
∑F = m × a Formula (1)
∑F: algebraic sum of forces in Newton (N)
m: mass in kg
a: acceleration in m/s²
T: cord tension in Newton (N)
Known data
m₁ = 12 kg
F = 66 N
a₁ = a₂ = 2.2 m/s²
Problem development
We can see in the attached figure the free body diagram of the masses and we replace the data in formula (1), considering that positive forces are the ones that go in the same direction of acceleration::
Mass 1 (m₁) free body diagram:
∑Fₓ = m₁ × a₁
66 - T = 12 × 2.2
66 - T = 26.4
66 - 26.4 = T
T = 39.6 N
Mass 2 (m₂) free body diagram:
∑Fₓ = m₂ × a₂
T = m₂ × 2.2
39.6 = m₂ × 2.2
m₂ = 39.6 ÷ 2.2
m₂ = 18 kg