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Lemur [1.5K]
3 years ago
9

Vinegar (C2H4O2) and baking soda (NaHCO3) react to form sodium acetate, water, and carbon dioxide. C2H4O2 + NaHCO3 ? How many to

tal oxygen atoms are expected in these products? A. 2 B. 3 C. 4 D. 5
Physics
2 answers:
aliya0001 [1]3 years ago
5 0

The total oxygen atoms that are exprected in the vinegar and baking soda reaction is three oxygen atoms.


Answer: B. 3




why;live

Schach [20]3 years ago
4 0

Answer: D. 5

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical equation will be:

C_2H_4O_2+NaHCO_3\rightarrow CH_3COONa+H_2O+CO_2

Thus there are 2 atoms of oxygen in vinegar and 3 atoms of oxygen in baking soda. Which means there are 5 oxygen atoms on reactant side.

Thus the products must also have 5 oxygen atoms.

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Answer:

Gamma rays

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Gamma rays is at the end of the electromagnetic spectrum, and has the highest energy. It propagates through space at 3x10^8 m/s and has the smallest wavelength and the highest frequency. It is given off by atoms of element as they undergo nuclear disintegration.

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Packages having a mass of 6 kgkg slide down a smooth chute and land horizontally with a speed of 3 m/sm/s on the surface of a co
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Answer:

t = 1.02 s

Explanation:

The computation of the time required is shown below:

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= 0.2 × 9.81

= 1.962 m/s^2

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5 0
2 years ago
A uniform beam with mass M and length L is attached to the wall by a hinge, and supported by a cable. A mass of value 3M is susp
Jobisdone [24]

Answer:

The tension is  T= \frac{11}{2\sqrt{3} } Mg

The horizontal force provided by hinge   Fx= \frac{11}{4\sqrt{3} } Mg

Explanation:

   From the question we are told that

          The mass of the beam  is   m_b =M

          The length of the beam is  l = L

           The hanging mass is  m_h = 3M

            The length of the hannging mass is l_h = \frac{3}{4} l

            The angle the cable makes with the wall is \theta = 60^o

The free body diagram of this setup is shown on the first uploaded image

The force F_x \ \ and \ \ F_y are the forces experienced by the beam due to the hinges

      Looking at the diagram we ca see that the moment of the force about the fixed end of the beam along both the x-axis and the y- axis is zero

     So

           \sum F =0

Now about the x-axis the moment is

              F_x -T cos \theta  = 0

     =>     F_x = Tcos \theta

Substituting values

            F_x =T cos (60)

                 F_x= \frac{T}{2} ---(1)

Now about the y-axis the moment is  

           F_y  + Tsin \theta  = M *g + 3M *g ----(2)

Now the torque on the system is zero because their is no rotation  

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          M* g * \frac{L}{2}  + 3M * g \frac{3L}{2} - T sin(60) * L = 0

            \frac{Mg}{2} + \frac{9 Mg}{4} -  T * \frac{\sqrt{3} }{2}    = 0

               \frac{2Mg + 9Mg}{4} = T * \frac{\sqrt{3} }{2}

               T = \frac{11Mg}{4} * \frac{2}{\sqrt{3} }

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The horizontal force provided by the hinge is

             F_x= \frac{T}{2} ---(1)

Now substituting for T

              F_{x} = \frac{11}{2\sqrt{3} } * \frac{1}{2}

                  Fx= \frac{11}{4\sqrt{3} } Mg

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All are expressed in Joules.

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