What is chromatography?

Upper C upper O subscript 2 (g) plus upper H subscript 2 (g) right arrow Upper C upper O (g) plus upper H subscript 2 upper O (l

Dominik [7]

Hydrogen gas

Explanation:

Expression:

CO₂ + H₂ → CO + H₂O

Hydrogen gas in this reaction is oxidized in the reaction.

In this manner, it is the reducing agent in the reaction.

A reducing agent is the specie in a chemical reaction that undergoes the process of oxidation.

It is marked by:

Addition of oxygen to a specie
Removal of hydrogen from a specie
Loss of electron by an atom
Increase in oxidation number
Increase in number of electronegative atoms surrounding a specie.

Here we see that H₂ fits this criteria perfectly well.

CO₂ is the one reduced.

learn more:

Oxidizing agent brainly.com/question/5558762

#learnwithBrainly

8 0

4 years ago

Read 2 more answers

A vessel of volume 22.4 dm3 contains 20 mol h2 and 1 mol n2 ad 273.15 k initially. All of the nitrogen reacted with sufficient h

NikAS [45]

Nitrogen combine with hydrogen to produce ammonia $\text{NH}_3$ at a $1:3:2$ ratio:

$\text{N}_2 \; (g) + 3 \; \text{H}_2 \; (g) \leftrightharpoons 2\; \text{NH}_3 \; (g)$

Assuming that the reaction has indeed proceeded to completion- with all nitrogen used up as the question has indicated. $3 \; \text{mol}$ of hydrogen gas would have been consumed while $2 \; \text{mol}$ of ammonia would have been produced. The final mixture would therefore contain

$17 \; \text{mol}$ of $\text{H}_2 \; (g)$ and
$2 \; \text{mol}$ of $\text{NH}_3 \; (g)$

Apply the ideal gas law to find the total pressure inside the container and the respective partial pressure of hydrogen and ammonia:

$\begin{array}{lll} P(\text{container}) &= & n \cdot R \cdot T / V \\ & = & (17 + 2) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=& 1.926 \times 10^{3} \; \text{kPa} \end{array}$
$\begin{array}{lll} P(\text{H}_2) &= & n \cdot R \cdot T / V \\ & = & (17) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=& 1.723 \times 10^{3} \; \text{kPa} \end{array}$
$\begin{array}{lll} P(\text{NH}_3) &= & n \cdot R \cdot T / V \\ & = & (2) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=& 2.037 \times 10^{2} \; \text{kPa} \end{array}$

6 0

3 years ago

What is the total number of elements in group 17 that are gases at room temperature and standard pressure?

White raven [17]

Answer:

Only to elements are gases at room temperature and standard pressure.

Fluorine and chlorine.

Explanation:

The group 17 is called halogen.

There are five elements in halogen group.

All halogens required one electrons to complete the octet and to get the noble gas electronic configuration.

All halogen elements have seven valance electrons.

Halogen elements:

Fluorine, chlorine, Bromine, iodine and astatine

Fluorine is gas at room temperature which s 25°C and standard pressure which is 1 atm.

It is present in the from of F₂.

Chlorine is also gas at room temperature and standard pressure.

It is present in the from of Cl₂.

The bromine is liquid under these condition.

Iodine and astatine are solids.

As we move down the group their melting and boiling points increases.

4 0

3 years ago

How many protons, electrons, and neutrons does the following isotope contain?

ASHA 777 [7]

Answer:

Explanation:

An atom is composed of a nucleus and electrons orbiting around it,and the nucleus itself contains protons and neutrons (with the exception of protium, an isotope of hydrogen with only a proton in the nucleus) because each element contains a specific and unique number of protons, but the number of neutrons can vary,an element, therefore, can have several variants, called isotopes, which differ slightly in the composition of the nucleus,the number of electrons can also change in an atom, giving us positive or negative ions.

=Br-79 has 79 nucleons. 79 protons and neutrons. We know that bromine has 35 protons, and 35 electrons, so all we need to do is subtract. 79 nucleons - 35 protons = 44 neutrons,

Subtract the atomic number from the mass number,the result gives you the number of neutrons in the isotope,look to see if the isotope has a charge, denoted by a superscript number and a plus or minus sign next to it,subtract the charge from the atomic number if the charge is positive,the result is the number of electrons in the isotope,add the absolute value of the charge to the atomic number if the charge is negative,the result is the number of electrons in the isotope.

= 35 from 79 and you will get 44. 44 is the number of neutrons in the Br-79 isotope.

79-Br+, that means:

It’s still a Br (bromine) atom, so it doesn’t change the number of protons //because changing the number of protons, it won’t be bromine anymore//

So bromine atom has 35 protons

So, isotope means many forms of atoms with the same element, which are different from atomic mass (or more clearly, the number of neutrons) → 79 (this number is shown for the atomic mass) - 35 = 44 neutrons

It has 35 protons, 34 electrons and 44 neutrons. The way to figure this out is - the protons of an element never change. So when you say bromine, you look it up on the Periodic table and you see its atomic number (aka # of protons) is 35. It will always be 35 for bromine. Then you take the charge into account. In this case, the charge is +1. Since protons can’t change, electrons must. One more proton equals one less electron. So 34 electrons. The atomic weight of a number (79 in this case) is = # of protons + # of neutrons. So neutrons = 79 - 35 = 44.

Hope this helps!

3 0

3 years ago

What is the first step in nuclear fission? 60 POINTS BRAINLIEST

kobusy [5.1K]

Answer:

<em><u>Energy is released.</u></em> In the first step, a uranium-235 atom absorbs a neutron, and splits into two new atoms (fission fragments), releasing three new neutrons and a large amount of binding energy.

5 0

3 years ago