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3 years ago

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How are atoms and elements alike and different?

1 answer:

Vika [28.1K]3 years ago

8 0

An element is an atom or group of the same type of atom in a concentrated, pure form. A molecule is a group of atoms that aren't all necessarily the same type of element. For example, in a sample of elemental iron, every atom in the sample will be an iron atom whereas in table salt, NaCl, half of the atoms are sodium atoms and the rest are chlorine atoms. Atoms are composed of a nucleus which has neutrally charged neutrons and positively charged protons, surrounded by a cloud of negatively charged electrons. Number of electrons and neutrons may vary from atom to atom of the same element, but the number of protons in the atom determine what element it is.

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2 years ago

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2 years ago

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Lorico [155]

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3 years ago

Silver chloride was reacted with magnesium hydroxide, in which magnesium displaced silver

Elza [17]

Answer:

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I hope it helped!

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3 years ago

Be sure to answer all parts.

MrRissso [65]

Answer: The molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

(c) 1.182 M

Explanation:

Molarity is the number of moles of a substance present in liter of a solution.

And, moles is the mass of a substance divided by its molar mass.

(a) Moles of ethanol (molar mass = 46 g/mol) is as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{28.5 g}{46 g/mol}\\= 0.619 mol$

Now, molarity of ethanol solution is as follows.

$Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.619 mol}{4.50 \times 10^{2} \times 10^{-3}L}\\= 1.38 M$

(b) Moles of sucrose (molar mass = 342.3 g/mol) is as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{21.6 g}{342.3 g/mol}\\= 0.063 mol$

Now, molarity of sucrose solution is as follows.

$Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.063 mol}{0.067 L} (1 mL = 0.001 L)\\= 0.94 M$

(c) Moles of sodium chloride (molar mass = 58.44 g/mol) are as follows.

$Moles = \frac{mass}{molar mass}\\= \frac{6.65 g}{58.44 g/mol}\\= 0.114 mol$

Now, molarity of sodium chloride solution is as follows.

$Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.114 mol}{0.0962 L}\\= 1.182 M$

Thus, we can conclude that the molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

(c) 1.182 M

4 0

3 years ago