The molar mass of a, b and c at STP is calculated as below
At STP T is always= 273 Kelvin and ,P= 1.0 atm
by use of ideal gas equation that is PV =nRT
n(number of moles) = mass/molar mass therefore replace n in the ideal gas equation
that is Pv = (mass/molar mass)RT
multiply both side by molar mass and then divide by Pv to make molar mass the subject of the formula
that is molar mass = (mass x RT)/ PV
density is always = mass/volume
therefore by replacing mass/volume in the equation by density the equation
molar mass=( density xRT)/P where R = 0.082 L.atm/mol.K
the molar mass for a
= (1.25 g/l x0.082 L.atm/mol.k x273k)/1.0atm = 28g/mol
the molar mass of b
=(2.86g/l x0.082L.atm/mol.k x273 k) /1.0 atm = 64 g/mol
the molar mass of c
=0.714g/l x0.082 L.atm/mol.K x273 K) 1.0atm= 16 g/mol
therefore the
gas a is nitrogen N2 since 14 x2= 28 g/mol
gas b =SO2 since 32 +(16x2)= 64g/mol
gas c = methaneCH4 since 12+(1x4) = 16 g/mol
Answer:
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- <u><em>Br²⁺ (g) → Br³⁺ (g) + e⁻</em></u>
Explanation:
1) The <u>first ionization energy</u> is the energy required to release an electron from a gas neutral atom.
Hence, this is the energy required for this process:
2) The <u>second ionization energy </u>is the energy required to release an electron from a gas ion with charge 1+.
Hence, this is the energy required for this process:
3) The<em><u> third ionization energy</u></em> is the energy required to release an electron from a gas ion with charge +2.
Hence, this is the energy required for this process:
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- <u><em>Br²⁺ (g) → B³⁺ (g) + e⁻</em></u>
I think that it would be the breakdown. Hope this helps!
Answer:
5
Explanation:
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