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Jlenok [28]
3 years ago
6

Help please! Will give brainliest to first correct answer!

Physics
1 answer:
Olegator [25]3 years ago
8 0

Answer:

1) Addition of a catalyst

2) To change the reaction rate of slope B to look like slope A, simply add a catalyst to speed up the rate of reaction, giving you a higher amount of products in a shorter amount of time (line A)

Explanation:

1 and 2)Two things can alter the rate of a reaction, either the addition of a catylist which will not alter the composition of the products or reactants, but will accelerate the reaction time, or an increase in temperature will also increase the rate at which a reaction will occur.

You could choose temperature also and have the same result, it's your choice both are correct, but catalyst is the easiest.

   

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Can someone help meeeeee... show how to solve it plzzzzzzzz
liubo4ka [24]
<h2>Right answer: 64 units</h2><h2></h2>

According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:

F=G\frac{m_{1}m_{2}}{r^2}

Where:

F is the module of the force exerted between both bodies

G is the universal gravitation constant.

m_{1} and m_{2} are the masses of both bodies.

r is the distance between both bodies

In this case we have a gravitation force F_{1}=16units, given by the formula written at the beginning. Let’s rename the distance r as d:

F_{1}=G\frac{m_{1}m_{2}}{d^2}     (1)

And we are asked to find the gravitation force F_{2} with a given distance of \frac{d}{2}:

F_{2}=G\frac{m_{1}m_{2}}{({\frac{d}{2})}^{2}}      

F_{2}=G\frac{m_{1}m_{2}}{{\frac{d^{2}}{4}}}     (2)

The gravity constant is the same for both equations, and we are assuming both masses are constants, as well. So, let’s isolate G m_{1}m_{2} in both equations:

From (1):

Gm_{1}m_{2}=F_{1}{d}^{2}     (3)

From (2):

Gm_{1}m_{2}=F_{2}\frac{{d}^{2}}{4}     (4)

If (3)=(4):

F_{1}{d}^{2}=F_{2}\frac{{d}^{2}}{4}     (5)

Now we have to find F_{2}:

F_{2}=F_{1}{d}^{2}\frac{4}{{d}^{2}}      

F_{2}=4F_{1}     (6)

If F_{1}=16 units:

F_{2}=(4)(16 units)        

F_{2}=64 units>>>>This is the new force of attraction     

3 0
3 years ago
What role if any does air resistance have on your results​
djyliett [7]
When air resistance acts, acceleration during a fall will be less than g because air resistance affects the motion of the falling objects by slowing it down. ... Air resistance depends on two important factors - the speed of the object and its surface area.
6 0
3 years ago
HELP PLEASE NOWWWW !!!! ( 1 )   Jill and Scott both road their bikes for 30 minutes.  Jill traveled 5 kilometers and Scott trave
katovenus [111]

#1

Jill and Scott both moves for 30 minutes

now if Jill cover 5 km distance and Scott cover 10 km distance

now we know that the formula of speed is given as

speed = \frac{distance}{time}

now we will have

speed of Jill

v = \frac{5}{0.5} = 10 km/h

speed of Scott

v = \frac{10}{0.5} = 20 km/h

so correct answer here is

<em>Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.</em>

<em>#2</em>

distance travelled by each car is given as

d = 400 miles

now here it is given that

time taken by green car

t_1 = 10 hours

time taken by yellow car

t_2 = 8 hours

now we can find the speed of two cars

speed = \frac{distance}{time}

speed of green car

v = \frac{400}{10} = 40 mph

speed of yellow car

v = \frac{400}{8} = 50 mph

so correct answer will be

<em>The yellow car was faster.  Yellow traveled at a speed of 50 mph while green was traveling at an average of 40 mph.</em>

6 0
3 years ago
Read 2 more answers
A 3-kg chunk of putty moving at 2 m/s collides with and sticks to a 5-kg bowling ball initially at rest. The bowling ball and pu
Oduvanchick [21]

Answer:

It's Momentum becomes 4

4 0
4 years ago
3. The car's mass is 400 kg. It moves at a velocity of 20 m/s. Calculate the car's momentum. *
Orlov [11]

Answer:

momentum=mass×velocity

momentum =400kg×20m/s=8000kg.m/s

7 0
3 years ago
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