The prefix your looking for is centi as in centimeter. I got this answer on google.
So please mark me as Brainiest.
Let say the two train cars are of masses
and ![m_2](https://tex.z-dn.net/?f=m_2)
now if the speed of two cars are
and ![v_2](https://tex.z-dn.net/?f=v_2)
then we can say that the momentum of two cars before they collide is given by
![P = m_1v_1 - m_2v_2](https://tex.z-dn.net/?f=P%20%3D%20m_1v_1%20-%20m_2v_2)
here two cars are moving in opposite direction so we can say that the net momentum is subtraction of two cars momentum.
Now since in these two car motion there is no external force on them while they collide
So the momentum of two cars are always conserved.
hence we can say that the final momentum of two cars will be same after collision as it is before collision
![P = m_1v_1 - m_2v_2](https://tex.z-dn.net/?f=P%20%3D%20m_1v_1%20-%20m_2v_2)
Answer:
c. You would weigh less on planet A because the distance between
you and the planet's center of gravity would be smaller.
Explanation:
The statement that best describes your weight on each planet is that you would weigh less on planet A because the distance between you and the planet's center of gravity would be smaller.
- This is based on Newton's law of universal gravitation which states that "the force of gravity between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distances between them".
Since weight is dependent on the force of gravity and mass, the planet with more gravitational pull will have masses on them weighing more.
- Since the distance between the person and the center of the planet is smaller, therefore, the weight will be lesser.
<u>Answer:</u>
Ball will move 92.8125 meter along the cliff in 7.5 seconds.
<u>Explanation:</u>
We have equation of motion ,
, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
In this case initial velocity = 0 m/s, acceleration = 3.3
, we need to calculate displacement when time = 7.5 seconds.
Substituting
![s=0*7.5+\frac{1}{2} *3.3*7.5^2\\ \\ =92.8125 meter](https://tex.z-dn.net/?f=s%3D0%2A7.5%2B%5Cfrac%7B1%7D%7B2%7D%20%2A3.3%2A7.5%5E2%5C%5C%20%5C%5C%20%3D92.8125%20meter)
So ball will move 92.8125 meter along the cliff in 7.5 seconds.