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3 years ago

The diameter of Circle A is _________. EF AG EG FG

Physics

2 answers:

Bond [772]3 years ago

6 0

Answer:

The diameter is EF

Explanation:

Given

Circle A (See attachment)

Required

Determine the line that represents the diameter

First, it should be noted that the diameter of a circle is always a straight line.

From the attachment, the circle has the following straight lines:

It should also be noted that the diameter passes through the center of a circle and divides it into two congruent parts.

From the list of straight lines above, only line EF satisfy this property

Hence, the diameter of the circle is line EF.

slava [35]3 years ago

6 0

I think EF would be your answer.

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Explanation:

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3 years ago

A drunken sailor stumbles 580 meters north, 530 meters northeast, then 480 meters northwest. What is the total displacement and

kvv77 [185]

Answer:

(a) 1294.66 m

(b) 88.44°

Explanation:

d1 = 580 m North

d2 = 530 m North east

d3 = 480 m North west

(a) Write the displacements in vector forms

$\overrightarrow{d_{1}}=580\widehat{j}$

$\overrightarrow{d_{2}}=530\left ( Cos45\widehat{i}+Sin45\widehat{j} \right )$

$\overrightarrow{d_{2}}=374.77\widehat{i}+374.77\widehat{j}$

$\overrightarrow{d_{3}}=480\left ( - Cos45\widehat{i}+Sin45\widehat{j} \right )$

$\overrightarrow{d_{3}}=-339.41\widehat{i}+339.41widehat{j}$

The resultant displacement is given by

$\overrightarrow{d}\overrightarrow{d_{1}}+\overrightarrow{d_{2}}+\overrightarrow{d_{3}}$

$\overrightarrow{d}=\left ( 374.77-339.41 \right )\widehat{i}+\left ( 580+374.77+339.41 \right )\widehat{j}$

$\overrightarrow{d}=35.36\widehat{i}+1294.18\widehat{j}$

magnitude of the displacement

$d ={\sqrt{35.36^{2}+1294.18^{2}}}=1294.66 m$

d = 1294.66 m

(b) Let θ be the angle from + X axis direction in counter clockwise

$tan\theta =\frac{1294.18}{35.36}=36.6$

θ = 88.44°

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Answer:

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1 year ago