Answer:
A = 2,8333 s
Explanation:
El periodo es definido como el tiene que toma de dar una oscilación.
En este caso realiza varias osicilacion por lo cual debemos encontrar el promedio del perdono.
T = t/n
calculemos
A = 34,0/ 12,0
A = 2,8333 s
The mineral with Mohs hardness would be scratched because the mineral with Mohs 7 hardness is stronger than the Mohs 5 mineral. Eventually, that mineral would turn into dust if you kept rubbing it.
Your weight would change but not your mass, the moon has less gravity so therefore you are going to be lighter :-)
Answer:
Explanation:
We shall apply Stefan's formula
E = AσT⁴
When T = 300
I₁ = Aσ x 300⁴
When T = 400K
I₂ = Aσ x 400⁴
I₂ / I₁ = 400⁴ / 300⁴
= 256 / 81
= 3.16
I₂ = 3.16 I₁ .
Answer:
Number of turns in secondary will be 7
Explanation:
We have given primary voltage ![V_p=120volt](https://tex.z-dn.net/?f=V_p%3D120volt)
Number of turns in the primary is ![N_p=3575](https://tex.z-dn.net/?f=N_p%3D3575)
Secondary voltage is given ![V_s=235mV=0.235volt](https://tex.z-dn.net/?f=V_s%3D235mV%3D0.235volt)
We have to find the number of turns in secondary
We know that ![\frac{N_p}{N_s}=\frac{V_p}{V_s}](https://tex.z-dn.net/?f=%5Cfrac%7BN_p%7D%7BN_s%7D%3D%5Cfrac%7BV_p%7D%7BV_s%7D)
So ![\frac{3575}{N_s}=\frac{120}{0.235}](https://tex.z-dn.net/?f=%5Cfrac%7B3575%7D%7BN_s%7D%3D%5Cfrac%7B120%7D%7B0.235%7D)
![N_s=6.60](https://tex.z-dn.net/?f=N_s%3D6.60)
As the number of turns can not be in decimal so number of turns will be 7