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bulgar [2K]
2 years ago
6

Liquid X of volume 0.5m3 and density 900kgm-3 was mixed with liquid Y of volume 0.4m3 and density 800kgm-3. What was the density

of the mixture?​
Physics
1 answer:
masha68 [24]2 years ago
8 0

Answer:

Density of the mixture = 855.56kgm-3

Explanation:

Density = Mass / Volume

Volume of Liquid X = 0.5m³

Density of Liquid X = 900kgm-3

Mass of Liquid X = Density × Volume

= 900kgm-3 × 0.5m³ = 450kg

Volume of Liquid Y = 0.4m³

Density of Liquid Y = 800kgm-3

Mass of Liquid Y = Density × Volume

= 800kgm-3 × 0.4m³= 320kg

As X and Y are mixed, we add their masses and volumes together:

Mass = 770kg

Volume = 0.9m³

Now we can find the density of the mixture:

Density = 770kg / 0.9m³ = 855.56kgm-3 (rounded to the 2nd decimal)

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3 years ago
Two iron bolts of equal Mass one at a hundred see another at 55 Sierra place in the insulated cylinder assuming the heat capacit
malfutka [58]

Answer:

T_2 = 77.5c

Explanation:

From the question we are told that

Temp of first boltsT_1=100

Temp of 2nd bolt T_2=55

Generally the equation showing the relationship between  heat & temperature is given by

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Generally heat released  by the iron bolt  = heat gained by the iron bolt

Generally solving mathematically

     -(0.45*m* (T_2-100  \textdegree c)) = 0.45*m*(T_2 -55\textdegree c)

     -(T_2-100 \textdegree c)) = (T_2 -55 \textdegree c)

      T_2 +T_2= 100 \textdegree c+55 \textdegree c

      T_2=\frac{155 \textdegree c}{2}

      T_2 = 77.5 \textdegree c

Therefore T_2 = 77.5 \textdegree c is the final temperature inside the container

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If you have a 1.0 m aqueous solution of NaCl, by how much will it increase the water’s boiling point, if KB = 0.512 °C/m? In oth
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<u>Answer:</u> The elevation in boiling point is 1.024°C.

<u>Explanation:</u>

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=ik_b\times m

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i = Van't Hoff factor = 2 (for NaCl)

\Delta T_b = change in boiling point  = ?

k_b = boiling point constant = 0.512^oC/m

m = molality = 1.0 m

Putting values in above equation, we get:

\Delta Tb=2\times 0.512^oC/m\times 1.0m\\\\\Delta Tb=1.024^oC

Hence, the elevation in boiling point is 1.024°C.

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