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bulgar [2K]
2 years ago
6

Liquid X of volume 0.5m3 and density 900kgm-3 was mixed with liquid Y of volume 0.4m3 and density 800kgm-3. What was the density

of the mixture?​
Physics
1 answer:
masha68 [24]2 years ago
8 0

Answer:

Density of the mixture = 855.56kgm-3

Explanation:

Density = Mass / Volume

Volume of Liquid X = 0.5m³

Density of Liquid X = 900kgm-3

Mass of Liquid X = Density × Volume

= 900kgm-3 × 0.5m³ = 450kg

Volume of Liquid Y = 0.4m³

Density of Liquid Y = 800kgm-3

Mass of Liquid Y = Density × Volume

= 800kgm-3 × 0.4m³= 320kg

As X and Y are mixed, we add their masses and volumes together:

Mass = 770kg

Volume = 0.9m³

Now we can find the density of the mixture:

Density = 770kg / 0.9m³ = 855.56kgm-3 (rounded to the 2nd decimal)

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Can anyone help me with this question please​
JulsSmile [24]

Explanation:

V=u+at

where,

v=final speed

u=initial speed,(starting speed)

a=acceleration

t=time

  1. v=u+at = 6=2+a*2

6=2+2a

2a=6-2

2a=4

a=4/2 = 2

a =2

2. to find time taken

v=u+at

25=5*2t

2t=25-5

2t=20

t=20/2

t=10sec

3. finding final speed

v=u+at

v=4+10*2

=4+20

v=24m/sec

5.v=u+at

=5+8*10

=5+80

V=85m/sev

6. v=u+at

8=u+4*2

8=u+8

U=8/8

u=1

these are your missing values

5 0
3 years ago
A selective college usually requires more years of _____ than a high school requires.
ipn [44]

Answer:

World languages__

Explanation:

A selective college usually requires more years of ___World languages__ than a high school requires. College graduates would look for jobs after college, they might have to travel to different countries. So, educating them about different language would give them a competitive edge to them. Moreover, in the age of globally integrated business community, knowing an extra language could work as cherry top on the cake.

5 0
3 years ago
A rock at the edge of a cliff has what kind of energy?
Marina CMI [18]
A rock at the edge of a cliff has potential energy because it isn't in motion, but is located in a place that motion could occur in the near future.
7 0
3 years ago
In a collision experiment, the ratio of the velocity change between two carts of equal inertia is found to equal 1.
VashaNatasha [74]

Answer:

A) Therefore if I double the masses with are in the two terrine they are simplified and the radii of the speeds remain the same

B) If the masses are maintained and the speeds are doubled, the radius of the two speeds remains the same

Explanation:

A vehicle crash problem must be solved with the equation of the moment,

Initial instant Before crash

              p₀ = m v₁ + mv₂

After the crash

            p_{f} = m v_{1f} + m v_{2f}

           p₀ = p_{f}

If the speed ratio before and after the crash is one

           p₀ / p_{f} = 1

We can assume that initially one of the cars was stopped

           m v₁₀ = m v_{2f}

           v₁₀ = v_{2f}

For the two speeds to be equal, the masses of the vehicles must be the same.

A) Therefore if I double the masses with are in the two terrine they are simplified and the radii of the speeds remain the same

B) If the masses are maintained and the speeds are doubled, the radius of the two speeds remains the same

5 0
3 years ago
A large truck collides head-on with a small compact car. During the collision: (A) the truck exerts a greater amount of force on
Yakvenalex [24]

Answer:

A The truck exerts greater force

Explanation:

During collision the truck exerts greater force due to its much larger mass coupled with the speed than the car exerts on it thereby damaging the car more

7 0
3 years ago
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