Estimate (a) the maximum, and (b) the minimum thermal conductivity values (in W/m-K) for a cermet that contains 76 vol% carbide
1 answer:
Answer:
The answer is below
Explanation:
Given that:
Volume of carbide () = 76% = 0.76, Volume of Nickel (
) = 100% - 76% = 24% = 0.24, thermal conductivities of carbide (
) = 30 W/m-K and thermal conductivities of meta. (
) = 67 W/m-K
a) The maximum thermal conductivity is given by:
Max =
b) The minimum thermal conductivity is given by:
Min =
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Answer:
A.) 0.3088
B.) 0.0017
C.) part A
Explanation:
A.)
B.)
C.) Since the seat performance for an individual pilot is more important than 39 different pilots.
A 260 ft (79.25m) length of size 4 AWG uncoated copper wire operating at a temperature of 75°c has a resistance of 0.0792 ohm.
Explanation:
From the given data the area of size 4 AWG of the code is 21.2 mm², then K is the Resistivity of the material at 75°c is taken as ( 0.0214 ohm mm²/m ).
To find the resistance of 260 ft (79.25 m) of size 4 AWG,
R= K * L/ A
K = 0.0214 ohm mm²/m
L = 79.25 m
A = 21.2 mm²
R = 0.0214 *
= 0.0214 * 3.738
= 0.0792 ohm.
Thus the resistance of uncoated copper wire is 0.0792 ohm