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yuradex [85]
3 years ago
8

Consider a building whose annual air-conditioning load is estimated to be 40,000 kWh in an area where the unit cost of electrici

ty is $0.10/kWh. Two air conditioners are considered for the building. Air conditioner A has a seasonal average COP of 2.3 and costs $5500 to purchase and install. Air conditioner B has a seasonal average COP of 3.6 and costs $7000 to purchase and install. All else being equal, determine which air conditioner is a better buy.
Engineering
1 answer:
sdas [7]3 years ago
7 0

Answer:

Air Conditioner B is a better buy for the consumer.

Explanation:

We are given

Annual load = 40,000kWh

Cost = $0.1/kWh

COPa = 2.3

COPb = 3.6

Purchase and Installation charge of A = $5500

Purchase and Installation charge of B = $7000  

We need to make our decision between a cheaper but inefficient and a costlier but efficient Air conditioner for the building.

We assume that all other factors for both the air conditioner remains same and are comparable in all other aspects except cost and efficiency.

The air conditioner which will cost less during its life time will be a better buy. The total cost of the unit during its lifetime like its (servicing, maintenance, etc) can be determined by performing a life cycle analysis, but a simpler method to determine it is by calculating the simple payback period. The energy and cost saving of more efficient Air conditioner is

Energy saving = (Annual energy usage of A) - (Annual energy usage of B)

                        = Annual Load( \frac{1}{COPa }  - \frac{1}{COPb}

                        = 40,000kWh( \frac{1}{2.3} - \frac{1}{3.6})

                        = 40000(0.157)

                        = 6280kWh/year

Cost saving = (6280kWh/year)*($0.1)  

                    = $628.02/year

The installation cost difference of the Air conditioner s

    Cost difference =  $7000-$5500

                               = $1500

Therefore a more efficient Air conditioner B will pay for $1500 cost differential for the first year.

A cost conscious buyer will go for a costly but efficient Air conditioner B which is a better buy in this case also the Air conditioner will last at least for 15 years. But it would be difficult if the cost of the electricity in the area of the consumer is less than $0.1/kWh or if the annual load is less than 40,000kWh.

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IrinaVladis [17]

Answer:

<h2> FA = 13 kN </h2><h2>FG = 15.3 kN</h2>

Explanation:

write each force in terms of magnitude and directions  

Fx = F sin Ф

Fy = F cos Ф

where Ф is to be measured from x axis.

∑F at y = o

FAy + FBy + FCy + FDy + FEy + FGy = 0

∑F at x = o

FAx + FBx + FCx + FDx + FEx + FGx = 0

Let  

FA = FA sin (110)   +   FA cos (110)

FB = 20 sin (270)  +  20 cos (270)

FC = 16 sin (140)    +  16 cos (140)

FD = 9 sin (40)       +  9 cos (40)

FE = 20 sin (270)    +  20 cos (270)

FG = FG sin (50)     +  FG cos (50)

add x and y forces:

FAx + FBx + FCx + FDx + FEx + FGx = 0

FAy + FBy + FCy + FDy + FEy + FGy = 0

FA sin (110)  + 0  + 16 sin (140)  + 9 sin (40)  + 0   + FG sin (50) = 0

FA cos (110) - 20 + 16 cos (140) + 9 cos (40) - 20 + FG cos (50 = 0

FA sin (110)  + 0  + 10.285  + 5.785  + 0   + FG sin (50) = 0

FA cos (110) - 20 - 12.257 + 6.894 - 20 + FG cos (50) = 0

FA sin (110)  + 16.070 + FG sin (50) = 0        

FA cos (110) - 45.363 + FG cos (50) = 0

solving for FA, and FG

FA = 13 kN

FG = 15.3 kN

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How many watts are consumed in a circuit having a power factor of 0. 2 if the input is 100 vac at 4 amperes?.
Anna71 [15]

The watts that are consumed is 80 watts.

<h3>What power factor?</h3>

The term power factor has to do with the measure of the efficiency of the use of energy. Recall that power is defined as the rate of doing work. The magnitude of the power factor shows the extent to which the power is used.

Now, to obtain the watts are consumed in a circuit having a power factor of 0. 2 if the input is 100 vac at 4 amperes we have;  V × I × PF = 100V × 4A × 0.2 = 80 watts.

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2 years ago
A rigid tank contains 1 kg of oxygen (O2) at p1 = 35 bar, T1 = 180 K. The gas is cooled until the temperature drops to 150 K. De
andreyandreev [35.5K]

Answer:

a. Volume = 13.36 x 10^-3 m³ Pressure = 29.17 bar  b. Volume = 14.06 x 10^-3 m³ Pressure = 22.5 bar

Explanation:

Mass of O₂ = 1kg, Pressure (P1) = 35bar, T1= 180K, T2= 150k Molecular weight of O₂ = 32kg/Kmol

Volume of tank and final pressure using a)Ideal Gas Equation and b) Redlich - Kwong Equation

a. PV=mRT

V = {1 x (8314/32) x 180}/(35 x 10⁵) = 13.36 x 10^-3

Since it is a rigid tank the volume of the tank must remain constant and hnece we can say

T2/T1 = P2/P1, solving for P2

P2 = (150/180) x 35 = 29.17bar

b. P1 = {RT1/(v1-b)} - {a/v1(v1+b)(√T1)}

where R, a and b are constants with the values of, R = 0.08314bar.m³/kmol.K, a = 17.22(m³/kmol)√k, b = 0.02197m³/kmol

solving for v1

35 = {(0.08314 x 180)/(v1 - 0.02197)} - {17.22/(v1)(v1 + 0.02197)(√180)}

35 = {14.96542/(v1-0.02197)} - {1.2835/v1(v1 + 0.02197)}

Using Trial method to find v1

for v1 = 0.5

Right hand side becomes =  {14.96542/(0.5-0.02197)} - {1.2835/0.5(0.5 + 0.02197)} = 31.30 ≠ Left hand side

for v1 = 0.4

Right hand side becomes =  {14.96542/(0.4-0.02197)} - {1.2835/0.4(0.4 + 0.02197)} = 39.58 ≠ Left hand side

for v1 = 0.45

Right hand side becomes =  {14.96542/(0.45-0.02197)} - {1.2835/0.45(0.45 + 0.02197)} = 34.96 ≅ 35

Specific Volume = 35 m³/kmol

V = m x Vspecific/M = (1 x 0.45)/32 = 14.06 x 10^-3 m³

For Pressure P2, we know that v2= v1

P2 = {RT2/(v2-b)} - {a/v2(v2+b)(√T2)} = {(0.08314 x 150)/(0.45 - 0.02197)} - {17.22/(0.45)(0.45 + 0.02197)(√150)} = 22.5 bar

3 0
3 years ago
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