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Svetach [21]
11 months ago
12

Part A Identify the zero-force members in the truss. (Figure 1) (Hint: Use both visual inspection and analysis.) Check all that

apply. DE UAB CD O BE BC BD AE
Engineering
1 answer:
balandron [24]11 months ago
5 0

The zero-force members in the truss are BE and BC. This is because they are the two non-collinear members.

<h3>How would you identify zero-force members in truss?</h3>

You would definitely identify zero-force members in a truss by the fact that a joint has only two non-collinear members and there is no external load or support reaction at that joint, then those two members are zero-force members.

Zero-force members in a truss are the structural members that significantly support no loading but aid in the stability of the truss.

Therefore, the zero-force members in the truss are BE and BC. This is because they are the two non-collinear members.  

To learn more about truss methods, refer to the link:

brainly.com/question/28016406

#SPJ1

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What i s the value of a capacitor with 250 V applied and has 500 pC of charge? (a) 200 uF (b) 0.5 pF (c) 500 uF (d) 2 pF
exis [7]

Answer:

(d) 2 pF

Explanation: the charge on capacitor is given by the expression

Q=CV

where Q=charge

           C=capacitance

           V=voltage across the plate of the capacitor

here we have given Q=500 pF, V=250 volt

using this formula C=\frac{Q}{V}

=500×10^{-12}×\frac{1}{250}

=2×10^{-12}

=2 pF

3 0
3 years ago
I am having trouble understanding how I got these wrong on my test. Is there something I am missing with xor?
GuDViN [60]

Answer:

  your answer is correct

Explanation:

You have the correct mapping from inputs to outputs. The only thing your teacher may disagree with is the ordering of your inputs. They might be written more conventionally as ...

 A B Y

 0 0 1

 0 1 0

 1 0 0

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That is, your teacher may be looking for the pattern 1001 in the last column without paying attention to what you have written in column B.

8 0
2 years ago
For goods-producing firms, at which of the following levels of resource planning does scheduling for individual subassemblies an
VashaNatasha [74]

Answer:

Disaggregation

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3 0
2 years ago
g A primary sedimentation basin is designed for an average flow of 0.3 m3/s. The TSS concentration in the influent is 240 mg/L.
yarga [219]

Answer:

(a) 0.243 m3/day

(b) 96 mg/l

(c) 0.426 m3/min

Explanation:

The sludge has an average solids concentration of 4 percent and considering TSS concentration in the influent of 240 mg/L then solids in sludge will be 0.04*240= 9.6 mg/L

Considering the average flow of 0.3 m3/s then mass of sludge per day will be given by 0.3*1000*9.6*60*60*24/1000000=248.832 kg/day

To get volume, considering specific gravity given as 1.025 and taking density of water as 1000 kg/m3 then density of sludge is 1025 kg/m3

Volume is mass/density hence 248.832/1025=0.2427629268292 m3/day

Approximately, the volume of sludge is 0.243 m3/day.

(b)

Efficiency of 60 percent is equivalent to 0.6

Efficiency=(influent concentration- flow rate)/influent concentration

0.6=(240-flow rate)/240

Flow rate= 96 mg/l

(c)

Cycle time= 0.243/0.57=0.4263157894736 m3/min

Rounded off, cycle time is 0.426 m3/day

3 0
3 years ago
Question 9
Mama L [17]

Answer:
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4. Light and adjust the torch.

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10 months ago
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