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Svetach [21]
1 year ago
12

Part A Identify the zero-force members in the truss. (Figure 1) (Hint: Use both visual inspection and analysis.) Check all that

apply. DE UAB CD O BE BC BD AE
Engineering
1 answer:
balandron [24]1 year ago
5 0

The zero-force members in the truss are BE and BC. This is because they are the two non-collinear members.

<h3>How would you identify zero-force members in truss?</h3>

You would definitely identify zero-force members in a truss by the fact that a joint has only two non-collinear members and there is no external load or support reaction at that joint, then those two members are zero-force members.

Zero-force members in a truss are the structural members that significantly support no loading but aid in the stability of the truss.

Therefore, the zero-force members in the truss are BE and BC. This is because they are the two non-collinear members.  

To learn more about truss methods, refer to the link:

brainly.com/question/28016406

#SPJ1

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Give me uses of a grinding machine in agriculture.
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Answer:

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4 0
3 years ago
An eddy current separator is to separate aluminum product from an input streamshredded MSW. The feed rate to the separator is 2,
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Answer:

<em>the % recovery of aluminum product is 80.5%</em>

<em>the % purity of the aluminum product is 54.7%</em>

<em></em>

Explanation:

feed rate to separator = 2500 kg/hr

in one hour, there will be 2500 kg/hr x 1 hr = 2500 kg of material is fed into the  machine

of this 2500 kg, the feed is known to contain 174 kg of aluminium and 2326 kg of rejects.

After the separation, 256 kg  is collected in the product stream.

of this 256 kg, 140 kg is aluminium.

% recovery of aluminium will be = mass of aluminium in material collected in the product stream ÷ mass of aluminium contained in the feed material

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% purity of the aluminium product = 140kg/256kg

x 100% = <em>54.7%</em>

8 0
3 years ago
What material resources and intellectual resources were used in self driving cars?
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3 years ago
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3 years ago
Steam enters an adiabatic condenser (heat exchanger) at a mass flow rate of 5.55 kg/s where it condensed to saturated liquid wat
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Answer:

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Explanation:

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m_{s}=5.55 \ kg/s

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\Delta T=10^{\circ}C

(Cp)_{w}=4.184 \ kJ/kg^{\circ}C

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⇒  m_{s}\times (\Delta h)=M_{w}\times(Cp)_{w}\times \Delta T

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⇒  5.55\times 2491=M_{w}\times 4.184\times 10\\

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