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3 years ago

Which solution will provide the LOWEST freezing point? Group of answer choices 1.2 M MgCl2 1.60 M KI 1.0 M Na2CO3 1.5 M NaCl

Chemistry

1 answer:

Anettt [7]3 years ago

8 0

Answer:

KI 1.0 M

Explanation:

Freezing point of a substance is a colligative property. This means that it depends on the amount of substance present is the system.

The freezing point is given by; T - Ta = K * m * i

Where;

T = freezing point of the pure solution

Ta = freezing point of the solution containing the solute

K = freezing point constant

m = molality of the solution

i= Van't Hoff factor

If we look at all the options provided, KI has only two particles in solution and a molality of 1.0 m hence it should exhibit the lowest freezing point of solution.

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3 years ago

Describe how particles of iron (Fe) an oxygen (O2) react to how produce oxide (Fe2O3), also known as rust.

forsale [732]

Answer:

Described by a redox reaction below

Explanation:

Iron(III) oxide is an ionic compound, since it consists of a metal, iron, and a nonmetal, oxygen.

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3 years ago

"Chilling" is most commonly practiced by:

zimovet [89]

Answer: Food production industry
Explanation:
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4 0

3 years ago

What is the mass of 4.5 x 10^22 molecules of hydrogen peroxide (H2O2)? Show your work in the space below.

valentinak56 [21]

Given :

Number of molecules of hydrogen peroxide, N = 4.5 × 10²².

To Find :

The mass of given molecules of hydrogen peroxide.

Solution :

We know, 1 mole of every compound contains Nₐ = 6.022 × 10²³ molecules.

So, number of moles of hydrogen peroxide is :

$n = \dfrac{N}{N_a}\\\\n = \dfrac{4.5\times 10^{22}}{6.022\times 10^{23}}\\\\n = 0.0747 \ moles$

Now, mass of hydrogen peroxide is given as :

m = n × M.M

m = 0.0747 × 34 grams

m = 2.54 grams

Hence, this is the required solution.

6 0

3 years ago

PLEASE HELP!!!!!!

pogonyaev

Answer:

$m_{B}^{theoretical}=0.365gB$

$Y=87.1\%$

Explanation:

Hello there!

In this case, since the reaction (A->B) have an initial amount of pure 4-aminobenzoic acid, the first step to compute the theoretical yield is to solve the following stoichiometric setup:

$m_{B}^{theoretical}=0.303gA*\frac{1molA}{137.14gA}*\frac{1molB}{1molA}*\frac{165.19 gB}{1molB}\\\\ m_{B}^{theoretical}=0.365gB$

Whereas A stands for 4-aminobenzoic acid and B for the benzocaine. Moreover, we compute the percent yield by dividing the actual yield (0.318 g) by the theoretical one (0.365 g):

$Y=\frac{0.318g}{0.365g} *100\%\\\\Y=87.1\%$

Best regards!

4 0

2 years ago