Answer:
16 times that of car A
Explanation:
Moving objects have kinetic energy which is calculated using the formula:
E=(1/2)mv² where m is the mass of the object and v is its velocity.
For car A, kinetic energy =1/2×m×15²
=112.5m........................................i
For car B, the kinetic energy =1/2×m×60²
=1800m......................................ii
dividing ii by i we get
1800m/112.5m= 16.07
Therefore The kinetic energy of car B is 16.07 times that of car A
For this one, all you really need to do is eliminate any answers
that are absurd or meaningless.
You can't increase a transformer.
You can't increase a circuit.
You can't increase a generator.
When the <em><u>current</u></em> through a coil of wire increases, the magnetic field
around the coil increases, so there would be more magnetic force
between the coil and a permanent magnet.
Answer:
Explanation:
initial velocity u = 32.7 m /s
final velocity v = 50.3 m /s
displacement s = 44500 m
acceleration a = ?
v² = u² + 2 a s
50.3² = 32.7² + 2 x a x 44500
2530.09 = 1069.29 + 89000a
a .016 m /s²
time taken t = ?
v = u + at
50.3 = 32.7 + .016 t
t = 1100 s
Answer:
i think it's 2km pm
Explanation:
2km x 30 60.. start was 30, and now your at 90.. we had to determine how much time it took.. so 2 is the average.. or atleast per minute and sorry it i still didnt answer ur question lol im just trynna help
Let us start from considering monochromatic light as an incidence on the film of a thickness t whose material has an index of refraction n determined by their respective properties.
From this point of view part of the light will be reflated and the other will be transmitted to the thin film. That additional distance traveled by the ray that was reflected from the bottom will be twice the thickness of the thin film at the point where the light strikes. Therefore, this relation of phase differences and additional distance can be expressed mathematically as

We are given the second smallest nonzero thickness at which destructive interference occurs.
This corresponds to, m = 2, therefore


The index of refraction of soap is given, then

Combining the results of all steps we get

Rearranging, we find


