Answer:
6.2 seconds
Explanation:
Using Newton's second law, ∑F=ma, we know the net force acting on the object is Force applied-Force of friction. The net force is 203 N. Newton's second law requires the mass of an object, not the weight force, so we will have to calculate the mass. We know that m*g=weight force, in this case, solve for the mass and you will get 210 kg. Now that we have the value of the net force and the mass, we can solve for acceleration.
=0.967 m/s^2. Now, since we have the acceleration, initial velocity(0 m/s), and the final velocity (6m/s) we will use these to solve for time using the kinematic equation Vf=Vi + at. Plug in the values we know and solve for time and you will get 6.2 seconds
Answer:
150mm
Explanation:
The correct answer to the given question is 150mm or 6 inch.
Atleast 150mm or 6 inches of a free conductor, measured from the point in box where it emerges from its cable sheath or raceway, must be left at each outlet, switch or junction point to lumination or connection of devices.
150mm of free conductor is required for the devices to be connected, this needs to be placed in the junctions
Answer:
![a=4\ m/s^2](https://tex.z-dn.net/?f=a%3D4%5C%20m%2Fs%5E2)
Explanation:
Given that,
Initial speed of a body, u = 0
Final speed of the body, v = 20 m/s
Time, t = 5 s
We need to find the acceleration of the body. We know that the acceleration of an object is equal to the rate of change of velocity divided by time taken. So,
![a=\dfrac{v-u}{t}\\\\a=\dfrac{20-0}{5}\\\\a=4\ m/s^2](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv-u%7D%7Bt%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7B20-0%7D%7B5%7D%5C%5C%5C%5Ca%3D4%5C%20m%2Fs%5E2)
So, the body's acceleration is equal to
.
Work done = force x distance
work done = 15 x 3
work done = 45J
Answer:
A.
Explanation:
In all actuality. The car may not be fully moving but since it's on a hill and the earth moves it makes the most sense. Also since the car is at a slope by the law of motion what goes up must come down so the car is in fact moving.