Answer:
A picture of a baseball being thrown tworad a batter at home plate.
Answer:
a = (v2 - v1) / t
From A to B (8 - 4) m/s / 1 s = 4 m / s^2
From A to D ( 7 - 4) m/s / 5 s = .6 m / s^2
Note these equations hold for "uniform" values
They say nothing about the acceleration at intermediate points - the equation just says that his average speed increased from 4 m/s to 7 m/s during a 5 sec period
Answer:
3
Explanation:
the answer is number three
<u>Solu</u><u>tion</u><u> </u><u>:</u><u>-</u>
Given that ,
- Initial Velocity of car = 44km / hr.
- Final Velocity of car = 0km / hr.
- Acceleration = -5km/hr².
To Find :
- Time taken to stop the car .
So , here use first equⁿ of motion which is ,

where ,
- v is final Velocity.
- u is Initial velocity.
- a is acceleration.
- t is time taken.
Now , substituting the respective values ,





