Well evaporation<span> is a gradual vaporization of a liquid on the surface whereas </span>boiling<span> is a rapid vaporization of a liquid only when it is heated to its </span>boiling<span> point. </span>
"These deep-ocean currents are driven by differences in the water's density, which is controlled by temperature (thermo) and salinity (haline). This process is known as thermohaline circulation. In the Earth's polar regions ocean watergets very cold, forming sea ice." this is what I found...
Answer:
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Explanation:
Given:
Area of pool = 3m×4m
Diameter of orifice = 0.076m
Outlet Velocity = 6.3m/s
Accumulation velocity = 1.5cm/min
Required:
Inlet flowrate
Solution:
The problem can be solved by this general formula.
Accumulation = Inlet flowrate - Outlet flowrate
Accumulation velocity × Area of pool = Inlet flowrate - Outlet velocity × Area of orifice
First, we need to convert the units of the accumulation velocity into m/s to be consistent.
Accumulation velocity = 1.5cm/min × (1min/60s)×(1m/100cm)
Accumulation velocity = 0.00025 m/s
We then calculate the area of the pool and the area of the orifice by:
Area of pool = 3 × 4 m²
Area of pool = 12m²
Area of orifice = πd²/4 = π(0.076m)²/4
Area of orifice = 0.00454m²
Since we have all we need, we plug in the values to the general equation earlier
Accumulation velocity × Area of pool = Inlet flowrate - Outlet velocity × Area of orifice
0.00025 m/s × 12m² = Inlet flowrate - 6.3m/s × 0.00454m²
Transposing terms,
Inlet flowrate = 0.316 m³/s
0.03185A current is required in the windings for that to occur.
- Solenoids are essentially coils of cord. These generate a magnetic subject which strives a pressure over a steel element.A solenoid is a fundamental time period for a coil of cord that we use as an electromagnet.
- We additionally consult with the tool which could convert electric power into mechanical power as a solenoid.
- Actually it generates a magnetic subject for developing linear movement from the electrical cutting-edge. With using a magnetic subject.
- Magnetic field at the centre of a solenoid of length 'L' having 'N' number of turns with a current 'I' is given by
...(1)
It is given that 1000 turns uniformly distributed over a length of 0.400 m produces a magnetic field of magnitude 1.00 ×10⁻⁴T .
Putting above values in equation (1) , we get
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