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Tasya [4]
2 years ago
9

In a titration of a solution of unknown concentration of calcium hydroxide against hydrochloric acid (concentration 0.9mol/dm3),

25cm3 of calcium hydroxide was neutralised by 22.5cm3 of hydrochloric acid. Calculate the concentration of the calcium hydroxide solution.
Ca(OH)2 + 2HCl -> CaCl2 + 2H2O
Chemistry
1 answer:
bearhunter [10]2 years ago
6 0
Hi dear
I hope that will be helpful

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The solubility of two slightly soluble salts of M^2+ , MA and MZ_2, are the same, 4 x 10^â4 mol/L.
LekaFEV [45]

Answer:

a) MZ₂

b) They have the same concentration

c) 4x10⁻⁴ mol/L

Explanation:

a) The solubility (S) is the concentration of the salt that will be dissociated and form the ions in the solution, the solubility product constant (Kps) is the multiplication of the concentration of the ions elevated at their coefficients. The concentration of the ions depends on the stoichiometry and will be equivalent to S.

The salts solubilization reactions and their Kps values are:

MA(s) ⇄ M⁺²(aq) + A⁻²(aq) Kps = S*S = S²

MZ₂(aq) ⇄ M⁺²(aq) + 2Z⁻(aq) Kps = S*S² = S³

Thus, the Kps of MZ₂ has a larger value.

b) A saturated solution is a solution that has the maximum amount of salt dissolved, so, the concentration dissolved is solubility. As we can notice from the reactions, the concentration of M⁺² is the same for both salts.

c) The equilibrium will be not modified because the salts have the same solubility. So, let's suppose that the volume of each one is 1 L, so the number of moles of the cation in each one is 4x10⁻⁴ mol. The total number of moles is 8x10⁻⁴ mol, and the concentration is:

8x10⁻⁴ mol/2 L = 4x10⁻⁴ mol/L.

7 0
3 years ago
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crimeas [40]

Answer:

part 1 is from the article

Explanation:

5 0
3 years ago
A sample of 5.72 g of liquid 1-propanol, C, H, O, is combustod with 43.4 g of oxygen gas, Carbon dioxide and water are
bekas [8.4K]

Answer:

2C3H8O + 9O2 ==> 6CO2 + 8H2O ... balanced equation

moles propanol = 5.26 g x 1 mol/60.1 g = 0.0875 moles

moles O2 = 31.8 g x 1 mol/31.9 g = 0.997 moles O2

Propanol is limiting based on the mol ratio in balance equation of 2 : 9

To find mass of O2 (excess reagent) left over, we will first find moles O2 used up.

moles O2 used = 0.0875 mol propanol x 9 mol O2/2 mol propanol = 0.394 moles O2 used

moles O2 left over = 0.997 mol - 0.394 mol = 0.603 mol O2 left

mass O2 left = 0.603 mol O2 x 32 g/mol = 19.3 g O2 left over

6 0
1 year ago
ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J.
timofeeve [1]

Complete question:

ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.

Answer:

The magnitude of q for the process 568 J.

Explanation:

Given;

change in internal energy of the gas, ΔU = 475 J

work done by the gas, w = 93 J

heat added to the system, = q

During gas expansion process, heat is added to the gas.

Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.

ΔU = q - w

q = ΔU +  w

q = 475 J  +  93 J

q = 568 J

Therefore, the magnitude of q for the process 568 J.

6 0
3 years ago
Which two types of reactions are also always redox reactions? Explain your answer.
mina [271]
Single displacement and combustion reactions are ALWAYS redox.
7 0
3 years ago
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