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Anuta_ua [19.1K]
3 years ago
12

1. How is energy transported from where it is generated to homes?

Chemistry
1 answer:
kvasek [131]3 years ago
5 0

Answer:

1. (put in simpler words so no one knows you got it off of brainly)

The electricity that flows to our homes is generated in power stations. From here, it flows through large transmission lines, which carry it to substations. Finally, distribution lines carry electricity from substations to houses, businesses, and schools.

2.  (put in simpler words so no one knows you got it off of brainly)

The transmission over long distances creates power losses. The major part of the energy losses comes from Joule effect in transformers and power lines. The energy is lost as heat in the conductors. This can be minimized by

answer choice 1: reducing technical losses including: replacing incorrectly sized transformers, improving the connection quality of conductors (power lines), and increasing the availability of reactive power by installing capacitor banks along transmission lines.

answer choice 2: (just in case answer choice 1 isn't what you're looking for)

You can reduce losses in your home by spreading out your electricity use evenly throughout the day, instead of running all your appliances at once.

Explanation:

hope this helped <3

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How many milliliters of 0.0050 N KOH are required to neutralize 41 mL of 0.0050 M H2SO4?
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Answer:

V KOH = 41 mL

Explanation:

for neutralization:

  • ( V×<em>C </em>)acid = ( V×<em>C </em>)base

∴ <em>C </em>H2SO4 = 0.0050 M = 0.0050 mol/L

∴ V H2SO4 = 41 mL = 0.041 L

∴ <em>C</em> KOH = 0.0050 N = 0.0050  eq-g/L

∴ E KOH = 1 eq-g/mol

⇒ <em>C</em> KOH = (0.0050 eq-g/L)×(mol KOH/1 eq-g) = 0.0050 mol/L

⇒ V KOH = ( V×<em>C </em>) acid / <em>C </em>KOH

⇒ V KOH = (0.041 L)(0.0050 mol/L) / (0.0050 mol/L)

⇒ V KOH = 0.041 L

4 0
3 years ago
A 25 liter balloon holding 1.5 moles of carbon dioxide leaks. If we are able to determine that 0.9 moles of carbon dioxide escap
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Answer:

10 Litre

Explanation:

Given that ::

v1 = 25L ; n1 = 1.5 mole ; v2 =? ; n2 = (1.5-0.9) = 0.6 mole

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v2 = (n2 * v1) / n1

v2 = (0.6 mole * 25 Litre) / 1.5 mole

v2 = 15 / 1.5 litre

v2 = 10 Litre

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Sulfur reacts with oxygen to produce sulfur dioxide. That is for every mole of sulfur reacted, one mole of sulfur dioxide also is produced. With the given mole of sulfur dioxide, the amount of sulfur in mass is determined by multiplying the number of moles to the molar mass of sulfur (32 g/mol).
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