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Kryger [21]
3 years ago
6

Looking at the name of an acid, how do you know if it only contains two

Chemistry
1 answer:
Maslowich3 years ago
3 0

Answer:

If it contains only 2 elements it will begin with “hydro” as in  

hydrochloric acid (HCl). If it contains more than 2 elements it is named based on the polyatomic (oxy) anion, as in nitric acid (HNO3), nitrous acid (HNO2), sulfuric acid (H2SO4). If the element has more than one possible charge, the value of the charge comes after the element name and before the word ion. Thus, Fe 2+ is the iron two ion, while Fe 3+ is the iron three ion.

Explanation:

You might be interested in
How many electrons do atoms like to have in their outer shell?
irakobra [83]

Explanation:

In general, atoms are most stable, least reactive, when their outermost electron shell is full. Most of the elements important in biology need eight electrons in their outermost shell in order to be stable, and this rule of thumb is known as the octet rule.

7 0
3 years ago
Carbohydrate metabolic enzymes bind D-glucose specifically. D-glucose has an estimated caloric value of 1 k.cal per 4 grams of c
Aleksandr [31]

Answer:

D) 0 k.cal per 4 grams

Explanation:

Genarally, glucose can be classified into two enantiomers such as d-glucose and l-glucose. The d-glucose is the most common sugar that bodies of living organisms use as source of energy. However, l-glucose is an organic compound and it is one of the aldohexose monosaccharides. It is the l-isomer of glucose and commonly refer to as a low-calorie sweetener. The l-glucose is  relatively indistinguishable in taste from d-glucose but cannot be used as a source of energy. Therefore, in the given problem:

if d-glucose has an estimated caloric value of 1 k.cal per 4 grams of carbohydrate, then the caloric value of l-glucose will be 0 k.cal per 4 grams.

3 0
3 years ago
When a gas in a cylinder is compressed at constant temperature by a piston, the pressure of the gas increases. Consider the foll
Marizza181 [45]

Answer:

Answer below!!

Explanation:

The volume of a gas is inversely proportional to presure keeping the temperature the same.

Hope I helped!!!

:)

4 0
3 years ago
Your paragraph containing
Sergeeva-Olga [200]

Answer:

1) Carbon tetrabromide, CBr₄

The name of the compound describes the the chemical composition of the compound by

a) Making mention of the elements in the compound, which are carbon and bromine

b) Specifying the quantity of the element that has more than one atom per mole of the compound, by making mention of the number in Roman

Here there are four bromine atoms per mole which is mentioned as tetra before the cation is mentioned as bromide or ide for-1 oxidation state for  the halogens

c) Indicating the oxidation state of the cation

2) Magnesium oxide, MnO

The name of the compound describes the the chemical composition of the compound by

a) Making mention of the elements in the compound, which are magnesium and oxygen

b) Specifying the quantity of the elements as one each by leaving out the numbering suffix in the name

c) Indicating the oxidation state of the cation, oxygen, as an oxide with a -2 charge

3) Magnesium Nitrate Mn(NO₃)₂

The name of the compound describes the the chemical composition of the compound by

a) Making mention of the elements and groups in the compound, which are magnesium and bitrate group

b) Specifying the group by the group name which consists of a means to determine the detailed content of the group

c) Indicating the oxidation state of the group, nitrate, which has  with a -1 charge

Explanation:

4 0
3 years ago
A smaple of 1cm cuvette gives an absorbance reading of 0.558. if they absorptivity for this sample is 15000l/(mol.cm), what is t
Mazyrski [523]
To solve this problem, we use Beer's Law: A= ε.l.c
A is the absorbance- 0,558
<span>ε is</span> the molar absorptivity- is <span>15000 </span><span><span>L⋅mol-1</span><span>cm-1</span></span>
<span>l is </span>the length of the cuvette- 1 cm
<span>c is</span> the molar concentration

Applying the formula,
0,558= 15000 x 1 x c
0,558/15000= c
c= <span>3.72×<span>10⁻⁵ </span> <span>mol⋅L<span>⁻¹</span></span></span>
<span />
3 0
3 years ago
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