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navik [9.2K]
3 years ago
5

How Many milligrams are in 94.2g?

Chemistry
2 answers:
nignag [31]3 years ago
8 0

Answer:

there is 94,200 milligrams in 94.2 grams

Explanation:

hope this helps, because 1,000 milligram is 1 gram

so 1,000x94.2(grams)=94,200

HOPE THIS HELPS A LITTLE

Natalija [7]3 years ago
5 0

Answer:

94,200 milligrams in 94.2 grams

To get answer multiply 94.2 by 1000.

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If 3.0g of H20 actually forms what is the percentage yield
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What is a physical property of water
Lyrx [107]

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Water has a lot of physical properties.

Explanation:

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Using the appropriate conversion factors in #2, convert 248 eggs into dozen of eggs
Marina CMI [18]

Answer:

20.67 dozen of eggs.

Explanation:

One dozen egg = 12 eggs

For 248 eggs.

we will divide the 248 by 12.

248/12

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Thus 20.7 dozen eggs are equals to 248 eggs.

It can be confirm by multiplying the 20.7 with 12.

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So, 20.67 is correct answer.

3 0
3 years ago
Write the Arrhenius Base reaction for the following: <br> Sr(OH)2
igor_vitrenko [27]

Answer:

Explanation:

Sr(OH)2 (aq) ⇔ Sr+2 (aq) + 2OH- (aq)

8 0
3 years ago
In CaCo3 + HCl = CaCl2 + H2O +CO3, how many liters of carbon dioxide gas, measured at STP, can be obtained from 45.0 g of calciu
Anon25 [30]

Answer:

B) 10.1 L

Explanation:

Hello,

In this case, for the given chemical reaction which should be corrected as shown below:

CaCO_3 + HCl \rightarrow CaCl_2 + H_2O +CO_2

Since 45.0g of calcium carbonate are used, the produced moles of carbon dioxide, via stoichiometry, are found to be:

n_{CO_2}=45.0g CaCO_3*\frac{1molCaCO_3}{100gCaCO_3}*\frac{1molCO_2}{1molCaCO_3}=0.45molCO_2

Finally, since STP conditions are referred to a temperature of 273.15K and 1 atm, the volume, by using the ideal gas equation result:

V=\frac{nRT}{P}=\frac{0.45mol*0.082\frac{atm*L}{mol*K}*273.15K }{1atm} \\ \\V=10.1L

So the answer is B) 10.1 L.

Best regards.

6 0
3 years ago
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