Answer:
Explanation:
As we know that there is no external torque on the system of two disc
then the angular momentum of the system will remains conserved
So we will have
now we have
also we have
now from above equation we have
now we have
Answer:
853776 J
Explanation:
The work-energy needs to pump water out of the pool is the product of the weight of water and distance h
E = Wh = mgh
Since water mass is a body of water we can treat it as the product of density 1000kg/m3 and volume, which is the product of base area and uniform height h
Therefore:
![E = mgh = g\rho A\int\limits^{2.2}_0 {h} \, dh\\E = 9.8*1000*30*12[h^2/2]^{2.2}_0 = 1764000(2.2^2 - 0^2) = 853776 J](https://tex.z-dn.net/?f=E%20%3D%20mgh%20%3D%20g%5Crho%20A%5Cint%5Climits%5E%7B2.2%7D_0%20%7Bh%7D%20%5C%2C%20dh%5C%5CE%20%3D%209.8%2A1000%2A30%2A12%5Bh%5E2%2F2%5D%5E%7B2.2%7D_0%20%3D%201764000%282.2%5E2%20-%200%5E2%29%20%3D%20853776%20J)
Friction can be useful when you trying to stop a car, also it can be useful in energy losses, increase wear and tear and produces heat
Answer:
Cold Front 3 // Stationary Front 1 // Warm Front 2 // Occluded Front 4
Explanation:
It's simple. Warm front means the warm air is pressing forward, which is why it's a warm front. Stationary Front, meaning they're at a standstill, also makes sense because stationary means not moving. Then since your last option is Occluded Front, since the others already have an answer, you have no choice but to match 4 with it. I took the quiz and got the answer right. :D
<h2>The frequency of tuning fork B is 475 Hz</h2>
Explanation:
The number of beats produced is equal to the frequency difference between the two tuning forks .
The frequency of A = 480 Hz
Thus the frequency of B can be = 485 or 475 Hz
When B is filed , its frequency increases and it start producing 2 beats with A .
Thus it frequency must be 475 Hz , by filing , it increases to 478 Hz .
By which it gives 480 - 478 = 2 beats per second .
This cannot happen with frequency 485 , because by filing this difference increases in place of decreasing .
