A quick, easy way to decide whether there was a chemical change
is to look and see whether there are NEW substances after the
event, that weren't there when it started.
This particular scenario started out with fat and sodium hydroxide (lye).
And then, suddenly, POOF ! Soap and glycerin showed up. Where did
THOSE come from ? They came from the molecules in fat and lye,
getting broken up and recombined to make different substances.
THAT's exactly a chemical change.
Answer:
- <u>C = Q/∆V . So the overall strategy here is to find the potential difference ∆V corresponding to a particular Q on an object, then take the ratio.</u>
Explanation:
Capacitance is the amount of charge something can hold for a given ap- plied potential difference between separated parts of the conductor:
Part (a): Velocity of the snowball
By conservation of momentu;
m1v1 + m2v2 = m3v3,
Where, m1 = mass of snowball, v1, velocity of snowball, m2 = mass of the hat, v2 = velocity of the hat, m3 = mass of snowball and the hat, v3 = velocity of snowball and the hut.
v2 = 0, and therefore,
85*v1 + 0 = 220*8 => v1 = 220*8/85 = 20.71 m/s
Part (b): Horizontal range
x = v3*t
But,
y = vy -1/2gt^2, but y = -1.5 m (moving down), vy =0 (no vertical velocity), g = 9.81 m/s^2
Substituting;
-1.5 = 0 - 1/2*9.81*t^2
1.5 = 4.905*t^2
t = Sqrt (1.5/4.905) = 0.553 seconds
Then,
x = 8*0.553 = 4.424 m
Answer:
zero
rank the magnitude of the average velocity over the first 2 second
<h2>Answer:</h2><h2>The depth of barge float=
3 cm</h2><h2>
Explanation:</h2>
Length of rectangular barge=5.2 m
Width of rectangular barge=2.4m
Mass of crate=410 kg
Let h be the height of barge float
Volume of barge float=
Density of water=
Weight of water displaced by barge=Buoyant force=-Weight of horse
1 m=100 cm
cm
Hence, the depth of barge float=3 cm
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