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3 years ago

A student measures the time it takes for two reactions to be completed.

Chemistry

2 answers:

dexar [7]3 years ago

6 0

Answer:

C. The rate of reaction B is lower

Studentka2010 [4]3 years ago

5 0

Answer:

Explanation:

because the left side of reactant is take more time to make a product than the first

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Determine the expected diffraction angle for the first-order diffraction from the (111) set of planes for FCC nickel (Ni) when m

faust18 [17]

Answer:

56°

Explanation:

First calculate $a:$

$a=2 R \sqrt{2}=2(0.1246) \sqrt{2}=0.352 \mathrm{nm}$

The interplanar spacing can be calculated from:

$d_{111}=\frac{a}{\sqrt{1^{2}+1^{2}+1^{2}}}=\frac{0.352}{\sqrt{3}}=0.203 \mathrm{nm}$

The diffraction angle is determined from:

$\sin \theta=\frac{n \lambda}{2 d_{111}}=\frac{1(0.1927)}{2(0.2035)}=0.476$

Solve for $\theta$

$\theta=\sin ^{-1}(0.476)=28^{\circ}$

The diffraction angle is:

$2 \theta=2\left(28^{\circ}\right)=56^{\circ}$

4 0

3 years ago

1. Do you think that the lightbulb and the Moon spheres are "to scale" compared to the real

Tems11 [23]

Answer:

Yes

Explanation: Had a question like this and I said yes and got it right

3 0

2 years ago

Why is the following chemical equation said to be balanced? it's not A or B

dmitriy555 [2]

Your answer should be d

8 0

3 years ago

The partial pressure of N2 in the air is 593 mm Hg at 1 atm. What is the partial pressure of N2 in a bubble of air a scuba diver

Evgen [1.6K]

Answer: Partial pressure of $N_{2}$ at a depth of 132 ft below sea level is 2964 mm Hg.

Explanation:

It is known that 1 atm = 760 mm Hg.

Also, $P_{N_{2}} = x_{N_{2}}P$

where, $P_{N_{2}}$ = partial pressure of $N_{2}$

P = atmospheric pressure

$x_{N_{2}}$ = mole fraction of $N_{2}$

Putting the given values into the above formula as follows.

$P_{N_{2}} = x_{N_{2}}P$

$593 mm Hg = x_{N_{2}} \times 760 mm Hg$

$x_{N_{2}}$ = 0.780

Now, at a depth of 132 ft below the surface of the water where pressure is 5.0 atm. So, partial pressure of $N_{2}$ is as follows.

$P_{N_{2}} = x_{N_{2}}P$

= $0.78 \times 5 atm \times \frac{760 mm Hg}{1 atm}$

= 2964 mm Hg

Therefore, we can conclude that partial pressure of $N_{2}$ at a depth of 132 ft below sea level is 2964 mm Hg.

8 0

3 years ago

How many bonding pairs in br2o

Evgen [1.6K]

There are 22 bonding parts

5 0

3 years ago