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zmey [24]
3 years ago
9

Question 3 (5 points)

Physics
1 answer:
Art [367]3 years ago
7 0

Answer:

There no image

Explanation:

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What is diffrence between damping and undamping?​
ICE Princess25 [194]

Answer:

Oscillation whose amplitude reduce with time are called damped oscillation. This happen because of the friction. In oscillation if its amplitude doesn't change with time then they are called Undamped oscillation

7 0
3 years ago
Read 2 more answers
Airplane flight recorders must be able to survive catastrophic crashes. Therefore, they are typically encased in crash-resistant
chubhunter [2.5K]

Answer:

3.2 MN

Explanation:

Given that

Mass of the box, m = 52 kg

Initial velocity of the box, u = 400 m/s

Final velocity of the box, v = 0 m/s

Time taken for the collision, t = 0.0065 s

Using the equation of motion

V = u + at, we turn around and make acceleration, a the subject of the formula. Now we have,

a = (v - u) / t

a = (0 - 400) / 0.0065

a = 61538.5 m/s²

The acceleration(which is negative acceleration or retar.dation actually) is 61538.5 m/s². We then proceed to is this acceleration in the basic Force equation, to get the magnitude of force needed.

Remember,

Force = mass * acceleration

F = ma, we already have our mass and acceleration, all we do is multiply

F = 52 * 61538.5

F = 3200002 N or 3.2 MN

Therefore, the magnitude of the force that acts on the box during collision is 3.2 MN

8 0
3 years ago
A very big hockey puck with mass 2.5 kg traveling 20 degrees north of east at 10.0 m/s strikes a puck with a mass of 4.0 kg trav
snow_tiger [21]

Answer:

Velocity = 0.47 m/s

Direction = 65 degrees South of east.

(295 degrees counter clockwise from + X axis).

Explanation:

Conservation of momentum along the X and Y directions can be used to determine the velocity of the 4 kg puck.

Along the X direction momentum conservation is as follows:  

2.5 cos 20 + 4.0 cos 90 = 2.5 cos 30 + 4 v cos α

⇒  v cos α = 2.5 ( cos 20 - cos 30) ÷ 4 = 0.46 m/s

2.5 sin 20 + 4 sin 90 = 2.5 sin 30 + 4 v sin α

v sin α = (2.5 sin 20 - 2.5 sin 30) ÷ 4 =  -0.0987 m/s

v = √(v² cos² α + v² sin² α) = √ (0.46² + (-0.0987)² = 0.47 m/s

Direction = α = tan⁻¹ (-0.0987/0.46) = -65 degrees = 65 degrees clock wise from +X axis or 295 degrees counter clockwise from +X axis

4 0
4 years ago
ANSWER FAST PLSSSSSS Use this diagram of the wave below to answer any questions that follow
tigry1 [53]

Answer:

1. Letter A indicates the crest.

2. Letter E indicates the wavelength.

3. Letter C indicates the trough.

Explanation:

1. Determination of the the crest.

A crest is simply defined as a point on a wave where the displacement is maximum (i.e highest).

Considering the diagram given above, the point where the displacement is maximum is A. Therefore, A is the crest of the wave.

2. Determination of the wavelength.

The wavelength of a wave is simply defined as the distance between two successive crest or trough.

Obeserving the diagram above, we can see that E gives the distance between two successive crest. Therefore, E is the wavelength of the wave.

3. Determination of the trough.

A trough is simply defined as a point on a wave where the displacement is minimum (i.e lowest). Thus we can say that the trough is the opposite of the crest.

Considering the diagram given above, the point where the displacement is minimum is C. Therefore, C is the trough of the wave.

7 0
3 years ago
If an 0.6kg apple is dropped from 0.5m height onto a seesaw and flips up a 0.25kg kiwi. To what height does that kiwi reach. Ass
natita [175]

answer

Height at which kiwi reach=1.2m

Solution

In this question we have given

mass of apple, m_{a} =.6kg

mass of kiwi,m_{a} =.25kg

height from which apple is dropped,H_{a} =.5m

Let the height at which kiwi reached is H_{k}

here,

We will apply law of conservation of energy

it means,

potential energy of kiwi= potential energy of apple

m_{k}\times g\times H_{k}= m_{a}\times g\times H_{a}......(1)

here g is gravitational acceleration

put values of m_{k} , g, H_{k}, m_{a} and H_{a} in equation 1

.25kg\times H_{k}=.6kg\times .5m\\H_{k}=\frac{.3kg\times m}{.25kg} \\H_{k}=1.2m

therefore, Height at which kiwi reach=1.2m

4 0
3 years ago
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