The answer would be a=5 m/s^2
I hope this helps you, have a great day!
Answer: So finally, the dimensional formula of the radius of gyration will be written as: [M0LT0]. The power of zero on the dimension of the mass and time shows that the mass and the time dimensions are zero for the radius of gyration. Hope this helps (:
The salesman is telling you the average magnitude of the car's acceleration.
| Acceleration | = (change in speed) / (time for the change)
| Acceleration | = (60 mi/hr) / (6 sec)
| Acceleration | = 10 miles/hr-sec
That would be 36,000 miles per hour squared,
or 0.0028 mile per second squared.
Answer:
5773.50269 Hz
23 A
Explanation:
= Inductance = 6 mH
= Capacitance = 5 μF
= Resistance = 3 Ω
= Maximum emf = 69 V
Resonant angular frequency is given by
The resonant angular frequency is 5773.50269 Hz
Current is given by
The current amplitude at the resonant angular frequency is 23 A
Answer:
Time of flight A is greatest
Explanation:
Let u₁ , u₂, u₃ be their initial velocity and θ₁ , θ₂ and θ₃ be their angle of projection. They all achieve a common highest height of H.
So
H = u₁² sin²θ₁ /2g
H = u₂² sin²θ₂ /2g
H = u₃² sin²θ₃ /2g
On the basis of these equation we can write
u₁ sinθ₁ =u₂ sinθ₂=u₃ sinθ₃
For maximum range we can write
D = u₁² sin2θ₁ /g
1.5 D = u₂² sin2θ₂ / g
2 D =u₃² sin2θ₃ / g
1.5 D / D = u₂² sin2θ₂ /u₁² sin2θ₁
1.5 = u₂ cosθ₂ /u₁ cosθ₁ ( since , u₁ sinθ₁ =u₂ sinθ₂ )
u₂ cosθ₂ >u₁ cosθ₁
u₂ sinθ₂ < u₁ sinθ₁
2u₂ sinθ₂ / g < 2u₁ sinθ₁ /g
Time of flight B < Time of flight A
Similarly we can prove
Time of flight C < Time of flight B
Hence Time of flight A is greatest .
