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astra-53 [7]
2 years ago
6

ANSWER FAST PLSSSSSS Use this diagram of the wave below to answer any questions that follow

Physics
1 answer:
tigry1 [53]2 years ago
7 0

Answer:

1. Letter A indicates the crest.

2. Letter E indicates the wavelength.

3. Letter C indicates the trough.

Explanation:

1. Determination of the the crest.

A crest is simply defined as a point on a wave where the displacement is maximum (i.e highest).

Considering the diagram given above, the point where the displacement is maximum is A. Therefore, A is the crest of the wave.

2. Determination of the wavelength.

The wavelength of a wave is simply defined as the distance between two successive crest or trough.

Obeserving the diagram above, we can see that E gives the distance between two successive crest. Therefore, E is the wavelength of the wave.

3. Determination of the trough.

A trough is simply defined as a point on a wave where the displacement is minimum (i.e lowest). Thus we can say that the trough is the opposite of the crest.

Considering the diagram given above, the point where the displacement is minimum is C. Therefore, C is the trough of the wave.

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The liquid contained in batteries that conducts electric charge is called the: solution, electrolyte, suspension, colloid
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Suppose two objects are gravitationally attracted to each other with some force F. If the mass of object 1 is multiplied by a fa
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A satellite is in a circular orbit about the earth (ME = 5.98 x 10^24 kg). The period of the satellite is 1.26 x 10^4 s. What is
Soloha48 [4]

Answer: V=5839.051m/s  

Explanation:

According to the <u>Third Kepler’s Law</u> of Planetary motion:

T^{2}=\frac{4\pi^{2}}{GM}a^{3}   (1)

Where;:

T=1.26(10)^{4}s is the period of the satellite

G is the Gravitational Constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}

M=5.98(10)^{24}kg is the mass of the Earth

a  is the semimajor axis of the orbit the satllite describes around the Earth (as we know it is a circular orbit, the semimajor axis is equal to the radius of the orbit).

On the other hand, the orbital velocity V is given by:

V=\sqrt{\frac{GM}{a}}   (2)

Now, from (1) we can find a, in order to substitute this value in (2):

a=\sqrt[3]{\frac{T^{2}GM}{4\pi}^{2}}   (3)

a=\sqrt[3]{\frac{(1.26(10)^{4}s)^{2}(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.98(10)^{24}kg)}{4\pi}^{2}}   (4)

a=11705845.57m   (5)

Substituting (5) in (2):

V=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.98(10)^{24}kg)}{11705845.57m}}   (6)

V=5839.051m/s   (7)  This is the speed at which the satellite travels

6 0
3 years ago
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