Answer:
Option C
Explanation:
Given that
Motor force is 250 N
Force of friction is 750 N
Weight is 8500 N
And, the normal force is 8500 N
Now based on the above information
Here length of the rector shows the relative magnitude forward force i.e. 250 N i..e lower than the frictional force i.e. backward and weight i.e. 8500 would be equivalent to the normal force
We are given a series circuit with two light bulbs. In this case, the light bulbs act as resistors in series and the total resistance is:
That is the sum of all the resistances in series in the circuit. To determine the voltage we can use Ohm's law:
Where "R" is the total resistance and "I" is the current in the circuit. Replacing we get:
Answer:
Option (2)
Explanation:
From the figure attached,
Horizontal component,
= 7.22 m
Vertical component,
= 9.58 m
Similarly, Horizontal component of vector C,
= C[Cos(60)]
= 6[Cos(60)]
=
= 3 m
= 5.20 m
Resultant Horizontal component of the vectors A + C,
m
= 4.38 m
Now magnitude of the resultant will be,
From ΔOBC,
=
=
= 6.1 m
Direction of the resultant will be towards vector A.
tan(∠COB) =
=
=
m∠COB =
= 46°
Therefore, magnitude of the resultant vector will be 6.1 m and direction will be 46°.
Option (2) will be the answer.
