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Lady bird [3.3K]

3 years ago

11

The worked examples of charged-particle motion are relevant to:______. a. a transistor. b. a cathode-ray tube. c. magnetic reson

ance imaging.d. cosmic rays. e. lasers.

1 answer:

Burka [1]3 years ago

3 0

Answer:

B. Cathode Ray Tube

Explanation:

In 1897, British physicist J. J. Thomson showed that cathode rays were composed of a negatively charged particle, which was later named the electron.

You might be interested in

How do you know an object is in motion?

puteri [66]

C
because an object need to be in motion to make any kind of movement

4 0

3 years ago

If you lose control of your vehicle and collide with a fixed object, such as a tree, at 60 m.p.h., the force of impact is the sa

My name is Ann [436]

You can compare the velocity of the car, 60 mph, with the velocity that a mass would acquire when falls from certain height.

First, convert 60 mph to m/s:

60 miles/h * 1.60 km/mile * 1000 m/km * 1h/3600s = 26.67 m/s

Second, calculate from what height a body in free fall reachs 26.67 m/s velocity when hits the floor.

free fall => Vf^2 = 2g*H => H = Vf^2 / (2g)

H = (26.67m/s)^2 / (2*9.8 m/s) = 36.2 m

If you consider that the height between the floors of a building is approximately 3.6 m, you get 36.2 m / 3.6 m/floor = 10 floors.

Then, you conclude that the force of impact is the same as driving you vehicle off a 10 story building.

7 0

4 years ago

A boat moves through the water with two forces acting on it. One is a 2.05 ✕ 103 N forward push by a motor, and the other is a 1

labwork [276]

Answer:

(a) a= 0.139 m/s²

(b) d= 4.45 m

(c) vf= 1.1 m/s

Explanation:

a) We apply Newton's second law:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass (kg)

a : acceleration (m/s²)

Data

F₁= +2.05 * 10³ N : forward push by a motor

F₂= -1.87* 10³ N : resistive force due to the water.

m= 1300 kg

Calculation of the acceleration of the boat

We replace data in the formula (1):

∑F = m*a

F₁+F₂= m*a

$a=\frac{F_{1} +F_{2} }{m}$

$a= \frac{2.05*10^{3} -1.87*10^{3}}{1300}$

a= 0.139 m/s²

b) Kinematics of the boat

Because the boat moves with uniformly accelerated movement we apply the following formulas:

d= v₀t+ (1/2)*a*t² Formula (2)

vf= v₀+at Formula (3)

Where:

d:displacement in meters (m)

t : time interval (s)

v₀: initial speed (m/s)

vf: final speed (m/s)

a: acceleration (m/s² )

Data

v₀ = 0

a= 0.139 m/s²

t = 8 s

Calculation of the distance traveled by the boat in 8 s

We replace data in the formula (2)

d= v₀t+ (1/2)*a*t²

d= 0+ (1/2)*(0.139)*(8)²

d= 4.45 m

c) Calculation of the speed of the boat in 8 s

We replace data in the formula (3):

vf= v₀+at

vf= 0+( 0.139)*(8)

vf= 1.1 m/s

6 0

4 years ago

What orientation of velocity and acceleration will cause something to initially speed up?

Temka [501]

-- If acceleration and velocity are in the same direction,
then the object is speeding up.

-- If acceleration and velocity are in opposite directions,
then the object is slowing down.

-- If acceleration is perpendicular to velocity, then the object
is moving on a circular curve at constant speed.

7 0

3 years ago

The only two forces acting on a body have magnitudes of 20 N and 35 N and directions that differ by 80°. The resulting accelerat

pantera1 [17]

Answer:

b) 2.2 kg

Explanation:

Net force acting on an object is the sum of the two forces acting on the body.

The net force is calculated using the parallelogram law of vectors.

F = $\sqrt{{A^{2}} + B^{2}+2 A B cos \theta}$

Here A = 20 N , B = 35 N and θ =80°

Net Force = F = 43.22 N

Acceleration = a = 20 m/s/s

Since F = ma, m = F/a = 43.22 / 20 = 2.161 kg = 2.2 kg

8 0

3 years ago