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Lady bird [3.3K]
3 years ago
11

The worked examples of charged-particle motion are relevant to:______. a. a transistor. b. a cathode-ray tube. c. magnetic reson

ance imaging.d. cosmic rays. e. lasers.
Physics
1 answer:
Burka [1]3 years ago
3 0

Answer:

B. Cathode Ray Tube

Explanation:

In 1897, British physicist J. J. Thomson showed that cathode rays were composed of a negatively charged particle, which was later named the electron. 

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An ideal solenoid having a coil density of 5000 turns per meter is 10 cm long and carries a current of 4.0
Diano4ka-milaya [45]
The rule that is used to get the strength of magnetic field at the center of solenoid (B) is:
B = <span>µ x n x I where:
</span>µ is the permeability of the medium where the solenoid is based. In this problem, the medium is air which means that µ = <span>µ </span><span>o = 4 pi x 10^-7 Tm/A
</span>I is the current passing (I = 4 amperes)
n is the number of turns per unit length (5000 turns)

Substituting in the mentioned equation, we find that:
B = 4 x 3.14 x 10^-7 x 5000 x 4 = 25.132 mT
5 0
3 years ago
What is the velocity of a 0.8kg ball that has a momentum of 3 kg*m/s?
Marysya12 [62]

The velocity is 3.75

5 0
3 years ago
Which of the following is a small electronic component made up of transistors (tiny switches) and other miniaturized parts?
Vlad [161]

Answer:

Integrated circuit (IC)

Explanation:

An integrated circuit ( IC ) is a semiconductor which contains multiple electronic components

interconnected to form a complete electronic function. Integrated circuits are the most essential part of all electronic products.

Modern integrated circuits contain as much as billions of circuit components such as transistors , diodes , resistors , and capacitors

onto a single monolithic die .

5 0
3 years ago
Multiple-Concept Example 7 and Interactive LearningWare 26.1 provide some helpful background for this problem. The drawing shows
Vlada [557]

Answer:

n = 1.4266

Explanation:

Given that:

refractive index of crystalline slab n = 1.665

let refractive index of fluid is n.

angle of incidence θ₁ = 37.0°

Critical angle \theta _c = sin^{-1} (\frac{n}{n_{slab}} )

sin \theta _ c =\frac{n}{n_{slab}}

According to Snell's law of refraction:

n sin \theta _1 = n_{slab}  \ sin \  (90- \theta_c)

At point P ; 90 - \theta _2  \leq \theta _c

\theta _2 = 90 - \theta _c

Therefore:

n \ sin \theta_1 = n_{slab} \sqrt{(1-sin^2 \theta _c)}  \\ \\ n \ sin \theta_1 = n_{slab}   \sqrt{(1- \frac{n}{n_{slab}} )}

Then maximum value of refractive index  n of the fluid is:

n = \frac{n_{slab}}{\sqrt{1+ sin^2 \theta _1 } }

n = \frac{1.665}{\sqrt{1+ sin^2 \  37} }

n = 1.4266

3 0
3 years ago
Two blocks are attached to opposite ends of a massless rope that goes over a massless, frictionless, stationary pulley. One of t
Marysya12 [62]

Answer:

<h2>1/7 kg</h2>

Explanation:

Find the diagram attached for better understanding of the question.

Given the mass of one of the blocks to be 1.0kg and accelerates downward at 3/4g.

g = acceleration due to gravity.

Let the block accelerating downward be M, mass of the other body be 'm' and the acceleration of the body M be 'a'.

M = 1.0 kg and a = 3.4g

According to newton's second law; \sum fy = ma_y

For body of mass m;

T - mg = ma ... (1)

For body of mass M;

Mg - T = Ma ... (2)

Adding equation 1 ad 2;

+Mg -mg = ma + Ma

Ma-Mg = -mg-ma

M(a-g) = -m(a+g)

Substituting M = 1.0 kg and a = 3/4g into the resulting equation;

3/4 g-g = -m(3/4 g+g)

3/4 g-g = -m(7/4 g)

-g/4 = -m(7/4 g)

1/4 = 7m/4

28m = 4

m = 1/7 kg

Therefore the mass of the other box is 1/7 kg

3 0
3 years ago
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