<span>To calculate the number of moles of aluminum, sulfur, and oxygen atoms in 4.00 moles of aluminum sulfate, al2(so4)3. We will simply inspect the "number" of aluminum, sulfur, and oxygen atoms available per one mole of the compound. Here we have Al2(SO4)3, which means that for every mole of aluminum sulfate, there are 2 moles of aluminum, 3 (1 times 3) moles of sulfur, and 12 (4x3) moles of oxygen. Since we have four moles of Al2(SO4)3 given, we simply multiply 4 times the moles present per 1 mole of the compound. So we have 4x2 = 8 moles of Al, 4x3 = 12 moles of sulfur, and 4x12 = 48 moles of oxygen.
So the answer is:
8,12,48
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<u>Answer:</u> The atomic symbol of the given element is 
<u>Explanation:</u>
The general isotopic representation of an element is given as: 
where,
Z represents the atomic number of the element
A represents the mass number of the element
X represents the symbol of an element
For the given isotope: 130-iodine
Mass number = 130
Atomic number = 53
Hence, the atomic symbol of the given element is
Answer:
The volume is 13, 69 L
Explanation:
We use the formula PV=nRT. We convert the temperature in Celsius into Kelvin and the pressure in mmHg into atm.
0°C= 273K---> 56°C= 56 + 273= 329K
760 mmHg----1 atm
719 mmHg----x= (719 mmHgx 1 atm)/760 mmHg= 0,95 atm
PV=nRT ---> V= (nRT)/P
V=( 0,482 molx 0,082 l atm/K mol x 329K)/0,95 atm
<em>V=13,68778526 L</em>
<span>Answer: B. Ionic solids have higher melting points than molecular solids.
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This is because the rest are false, as solids are able to melt, and do have melting points. Also, not all solids have the same melting points.
