Answer:
(a). The frequency of this standing wave is 0.782 kHz.
(b). The frequency of the fundamental standing wave in the air is 1.563 kHz.
Explanation:
Given that,
Length of tube = 11.0 cm
(a). We need to calculate the frequency of this standing wave
Using formula of fundamental frequency
Put the value into the formula
(b). If the test tube is half filled with water
When the tube is half filled the effective length of the tube is halved
We need to calculate the frequency
Using formula of fundamental frequency of the fundamental standing wave in the air
Put the value into the formula
Hence, (a). The frequency of this standing wave is 0.782 kHz.
(b). The frequency of the fundamental standing wave in the air is 1.563 kHz.
Answer:
D
Explanation:
D is the most likely answer because as we become more modernized as a whole we will progressively need to fill more positions in support specialty fields.
Answer:
C. I think
Explanation:
C. permanent positive charges
Answer:
alkaline earth metals
Group 2 metals, the alkaline earth metals, have 2 valence electrons, and thus form M2+ ions. The halogens, Group 17 , reach a full valence shell upon reduction, and thus form X− ions
Explanation:
Answer:
The mass of the meter stick is 
Explanation:
Here since the meter stick is in equilibrium position its net torque and net force should be equal to zero
Since at the begging the meter stick is balanced at center of the meter stick that means its center of mass should be present at 
Now lets consider the later case where stick is balanced by two 5.12 g coins .
Here torque due to two coins = 
Torque due to weight of meter stick = 
= 
where m = mass of the meter stick
Here 
.
Upon equating we will be getting mass of the meter stick =
