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3 years ago

5

What is a difference between an object's speed and velocity?

2 answers:

alisha [4.7K]3 years ago

8 0

Answer:

velocity is the magnitude and the direction and speed is the distance something traveled in a certain amount of time

SOMETHING:

hope this helps

Aleks04 [339]3 years ago

5 0

Answer:

.

Explanation:

Speed, being a scalar quantity, is the rate at which an object covers distance. ... On the other hand, velocity is a vector quantity; it is direction-aware. Velocity is the rate at which the position changes. The average velocity is the displacement or position change (a vector quantity) per time ratio.

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A scientist pours 0.120 L of solution A into an Erlenmeyer flask. She adds 2.345 L of solution B. How many significant figures a

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3 years ago

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3 years ago

Problem One: A beam of red light (656 nm) enters from air into the side of a glass and then into water. wavelength, c. and speed

Ivanshal [37]

Answer:

Part a)

$f_w = f_g = 4.57 \times 10^{14} Hz$

Part b)

$\lambda_w = 492 nm$

$\lambda_g = 437.3 nm$

Part c)

$v_w = 2.25 \times 10^8 m/s$

$v_g = 2.0 \times 10^8 m/s$

Explanation:

Part a)

frequency of light will not change with change in medium but it will depend on the source only

so here frequency of light will remain same in both water and glass and it will be same as that in air

$f = \frac{v}{\lambda}$

$f = \frac{3 \times 10^8}{656 \times 10^{-9}}$

$f = 4.57 \times 10^{14} Hz$

Part b)

As we know that the refractive index of water is given as

$\mu_w = 4/3$

so the wavelength in the water medium is given as

$\lambda_w = \frac{\lambda}{\mu_w}$

$\lambda_w = \frac{656 nm}{4/3}$

$\lambda_w = 492 nm$

Similarly the refractive index of glass is given as

$\mu_w = 3/2$

so the wavelength in the glass medium is given as

$\lambda_g = \frac{\lambda}{\mu_g}$

$\lambda_g = \frac{656 nm}{3/2}$

$\lambda_g = 437.3 nm$

Part c)

Speed of the wave in water is given as

$v_w = \frac{c}{\mu_w}$

$v_w = \frac{3 \times 10^8}{4/3}$

$v_w = 2.25 \times 10^8 m/s$

Speed of the wave in glass is given as

$v_g = \frac{c}{\mu_g}$

$v_g = \frac{3 \times 10^8}{3/2}$

$v_g = 2 \times 10^8 m/s$

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3 years ago

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3 years ago

malcom is doing a wheely on his motorcycle and moving at 20 m/s with a momentum of 6000 kg m/s when he lays her down. The mass o

rodikova [14]

Answer:

110 kg

Explanation:

The momentum of the Malcom+motorcycle system is given by:

$p=(m+M)v$

where

(m+M) is the total mass of the system, with

m = mass of Malcom

M = 190 kg (mass of the motorcycle)

v = 20 m/s velocity

Since we know the momentum:

p = 6000 kg m/s

We can re-arrange the equation to find the mass of Malcom:

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3 years ago