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Alenkinab [10]
3 years ago
9

A ship is travelling due east at 30 km/hr and a boy runs across the deck

Physics
1 answer:
dsp733 years ago
8 0

Answer:

Vr = 20 [km/h]

Explanation:

In order to solve this problem, we have to add the relative velocities. We must remember that velocity is a vector, therefore it has magnitude and direction. We will take the sea as the reference measurement level.

Let's take the direction of the ship as positive. Therefore the boy moves in the opposite direction (Negative) to the reference level (the sea).

V_{r}=30-10\\V_{r}=20 [km/h]

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dezoksy [38]
The answer is 0k because 143c equals nothing
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1 year ago
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For the image of the overhead projector to be in focus, the distance from the projector lens to the image, <img src="https://tex
rjkz [21]
Given:
distance from the projector lens to the image, di
projector lens focal length, f
distance from the transparency to the projector lens, do

thin lens equation: 1/f = 1/di + 1/do
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convert feet to inches, for uniformity.
1 foot = 12 inches
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Adding fractions, denominator must be the same.

1/f = (1/96 * 1/1) + (1/4 * 24/24)
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4 0
3 years ago
An electric dipole consisting of charges of magnitude 1.70 nC separated by 6.80 μm is in an electric field of strength 1160 N/C.
bazaltina [42]

Answer:

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The potential energie dipole  is described by the expression

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Antiparallel orientation

                       θ = 180º

                      cos 180 = -1

                      U2 = -1.35 10⁻¹¹ J

The difference in energy between these two configurations is the subtraction of the energies

                         ΔU = | U1 -U2 |

                         ΔU = 1.35 10-11 - (-1.35 10-11)

                         ΔU = 2.7 10 -11 J

6 0
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