Answer:
Electrons will flow from left to right through the wire.
Pb^2+ ions will be reduccd to Pb metal.
The concentration of Sn2+ ions in the left compartment will increase.
Explanation:
Looking at the relative electrode potentials of the two metals
Sn= -0.14
Pb=-0.13
Tin is expected to function as the anode (left hand half cell) and lead as the anode (right hand half cell) tin oxidizes to sn^2+ hence its concentration increases on the left compartment while lead is reduced to ordinary lead metal on the right hand half cell . since oxidation occurs on the left hand side, electrons flow from left to right.
<u>Answer:</u> Carbon-carbon double bond is stronger and shorter than the single bond.
<u>Explanation:</u>
It is given that carbon-carbon double bond has greater energy than the carbon-carbon single bond.
Bond energy is directly proportional to the bond strength, which means that the double bond will have greater strength than single bond and triple bond has the greatest strength of all the bonds.

Bond energy is inversely proportional to the bond length of the carbon-carbon bond. This means that more is the bond energy, shorter will be the bond and vice-versa.

Hence, carbon-carbon double bond is stronger and shorter than the single bond.
Answer: Option (d) is the correct answer.
Explanation:
Metals are the species which contain more number of electrons.
When a specie loses electrons then it acquires a positive charge. Whereas when an atom gains electrons then it acquires a negative charge.
Thus, as metals have more number of electrons, therefore, in order to gain stability metals readily lose electrons.
Hence, metals naturally form positive ions, by losing electrons to empty the valence shell.
A reaction is when two or more pure substances combine with each other to form another identity of pure substances. In general from, it is written as:
A + B → C + D
The substances A and B are the reactants, while the substances C and D are the products. Therefore, in a reaction, the products are found at the end or right side of the reaction.