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Nadya [2.5K]
4 years ago
10

What is normalization ​

Physics
2 answers:
tatuchka [14]4 years ago
7 0

Answer:

Normalization is a systematic approach of decomposing tables to eliminate data redundancy. It is a multi-step process that puts data into tabular form, removing duplicated data from the relation tables.

Explanation:

borishaifa [10]4 years ago
4 0

Answer:

the process of bringing or returning something to a normal condition or state.

Explanation:

In "your own words"- Normalization is when you change something back into it's average form.

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Lumbar nerves transmit signals that allow us to?
labwork [276]
Lumbar nerves transmit signals that allow us to walk. They are a pivotal part of the human body, and without them we would be immobile. Hope this helps.
7 0
4 years ago
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Name one contact force and one force that acts through a force field
nirvana33 [79]
A contact force is a type of force which act on an object by coming in contact with the object. Examples of contact force that acts through a force field are: applied force, frictional force, air resistance force, tension, spring force, etc.
  Examples of forces that act through a force field are gravitational force, electromagnetic force, the weak interaction and the strong interaction.
5 0
4 years ago
Calculate the electric field at the center of a square
pantera1 [17]

Answer:

E_y=1175510.2\ N.C^{-1}

The Magnitude of electric field is in the upward direction as shown directly towards the charge q_1.

Explanation:

Given:

  • side of a square, a=52.5\ cm
  • charge on one corner of the square, q_1=+45\times 10^{-6}\ C
  • charge on the remaining 3 corners of the square,q_2=q_3=q_4=-27\times 10^{-6}\ C

<u>Distance of the center from each corners</u>=\frac{1}{2} \times diagonals

diagonal=\sqrt{52.5^2+52.5^2}

diagonal=74.25\cm=0.7425\ m

∴Distance of center from corners, b=0.3712\ m

Now, electric field due to charges is given as:

E=\frac{1}{4\pi\epsilon_0}\times \frac{q}{b^2}

<u>For charge q_1 we have the field lines emerging out of the charge since it is positively charged:</u>

E_1=9\times 10^9\times \frac{45\times 10^{-6}}{0.3712^2}

  • E_1=2938775.5\ N.C^{-1}

<u>Force by each of the charges at the remaining corners:</u>

E_2=E_3=E_4=9\times 10^9\times \frac{27\times 10^{-6}}{0.3712^2}

  • E_2=E_3=E_4=1763265.3\ N.C^{-1}

<u> Now, net electric field in the vertical direction:</u>

E_y=E_1-E_4

E_y=1175510.2\ N.C^{-1}

<u>Now, net electric field in the horizontal direction:</u>

E_y=E_2-E_3

E_y=0\ N.C^{-1}

So the Magnitude of electric field is in the upward direction as shown directly towards the charge q_1.

8 0
3 years ago
How do you find the velocity after a collision
Evgen [1.6K]

Answer:

In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.

Explanation:

7 0
4 years ago
Car B is being pushed by a force of 22000 N. If it has a mass of 1375 kg.,
Burka [1]

Answer:

a = 16 m/s²

General Formulas and Concepts:

<u>Dynamics</u>

Newton's Law of Motions

  • Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motion
  • Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)
  • Newton's 3rd Law of Motion: For every action, there is an equal and opposite reaction<u> </u>

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] F = 22000 N

[Given] m = 1375 kg

[Solve] a

<u>Step 2: Find Acceleration</u>

  1. Substitute in variables [Newton's 2nd Law of Motion]:                                 22000 N = (1375 kg)a
  2. Isolate <em>a</em>:                                                                                                            16 m/s² = a
  3. Rewrite:                                                                                                             a = 16 m/s²
5 0
3 years ago
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