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V125BC [204]
2 years ago
7

A track consists spring launcher on one end. A spring which is compressed 0.5 m has a

Physics
1 answer:
patriot [66]2 years ago
4 0

(a) The velocity of the first ball before the collision with the second ball is 11.18 m/s.

(b) The final velocity of the two balls after the collision is determined as 5.59 m/s.

<h3>Speed of the block when pushed by the spring</h3>

The speed of the block when pushed by the spring is calculated as follows;

K.E = Ux

¹/₂mv² = ¹/₂kx²

mv² = kx²

v² = kx²/m

v² = (25 x 0.5²)/0.05

v² = 125

v = 11.18 m/s

<h3>Final velocity of the two balls after the collision</h3>

The velocity of the two balls after the collision is calculated as follows;

Pi = Pf

where;

  • Pi is initial momentum
  • Pf is final momentum

m1u1 + m2u2 = v(m1 + m2)

0.05(11.18) + 0.05(0) = v(0.05 + 0.05)

0.559 = 0.1v

v = 5.59 m/s

Learn more about velocity here: brainly.com/question/4931057

#SPJ1

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Match these names with the correct statements. 1. said sun revolved around earth Clyde Tombaugh 2. said earth revolved around su
Murljashka [212]

Answer:

1. Ptolemy.

2. Nicolaus Copernicus.

3. Tycho Brahe

4. Galileo Galilei

5. Isaac Newton

6. William Herschel

7. Johann Galle

8. Clyde Tombaugh

9. Albert Einstein.

10. Edwin Hubble

11. Karl Jansky.

12. Grote Weber.

Explanation:

1. Ptolemy: said sun revolved around earth.

2. Nicolaus Copernicus: aid earth revolved around sun.

3. Tycho Brahe: analyzed motions of planets.

4. Galileo Galilei: first used refracting telescope for astronomy.

5. Isaac Newton: invented reflecting telescope.

6. William Herschel: discovered the planet Uranus.

7. Johann Galle: discovered the planet Neptune.

8. Clyde Tombaugh: discovered the dwarf planet Pluto.

9. Albert Einstein: developed special and general theories of relativity.

10. Edwin Hubble: demonstrated that universe is expanding.

11. Karl Jansky: discovered radio waves from the center of the Milky Way.

12. Grote Weber: an amateur astronomer who built the first radio telescope.

8 0
3 years ago
A particular planet has a moment of inertia of 9.74 × 1037 kg•m2 and a mass of 5.98 × 1024 kg. Based on these values, what is th
goldfiish [28.3K]
Assuming the planet can be treated as a solid sphere,I=\frac{2}{5}MR^2

(9.74 x 10^37 kg-m²) = (2/5)(5.98 x 10^24 kg)R²

R = 6.38 x 10^6 m
4 0
3 years ago
A bucket filled with water has a mass of 54 kg and is hanging from a rope that is wound around a 0.050 m radius stationary cylin
Lubov Fominskaja [6]

Answer:

The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

Explanation:

Given that,

Mass of bucket = 54 kg

Radius = 0.050 m

We need to calculate the magnitude of the torque the bucket produces around the center of the cylinder

Using formula of torque

\tau=F\times r

\tau=mg\times r

Where, m = mass

g = acceleration due to gravity

r = radius

Put the value into the formula

\tau=54\times9.8\times0.050

\tau=26.46\ N-m

Hence, The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

3 0
3 years ago
How does fabric softener help prevent static electricity?
algol13

Answer:

Dryer sheets stop static cling by absorbing static electricity formed by different fabrics during your dryer cycle. The fabric softeners that coat dryer sheets are positively charged ions to balance the electrons and ions that cause static cling, leaving you with soft clothes without the static.

Explanation:

3 0
2 years ago
A student launches a small 0.5 kg rocket with an initial speed of 30 m/s at an angle of 60°. Approximately how much time will th
Elena L [17]

Answer:

t=5.30s

Explanation:

The high reached by a proyectile in an uniformly accelerated motion is given by:

y=v_{0y}t-\frac{gt^2}{2}

The time that the rocket spends in the air is obtained for y = 0, since this is the time that the rocket travels before touching the ground. Recall that v_{0y}=v_0sin\theta. Solving for t:

0=(v_0sin\theta) t-\frac{gt^2}{2}\\\frac{gt}{2}=v_0sin\theta\\t=\frac{2v_0sin\theta}{g}\\t=\frac{2(30\frac{m}{s})sin(60^\circ)}{9.8\frac{m}{s^2}}\\t=5.30s

5 0
4 years ago
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