<h3>Answer</h3>
Heat : 12 kJ, to maintain hydrogen bonds
<h3>Further explanation</h3>
Given
A 2.00mole sample ⇒ n = 2 mol
H₂O(s) at 0°C melted, producing H₂O(l) at 0°C
Required
the amount of heat required
the changes that took place
Analysis
Conversion of mol to mass
Use formula of Heat :
Q = mLf (melting/freezing)
Lf=latent heat of fusion (for water=334 J/g)
Solution
mass H₂O(MW=18 g/mol) :

Heat required :

The absorbed heat is used to maintain hydrogen bonds in water molecules (there are two hydrogen bonds per molecule)
Paraphrase
The amount of heat required : 12 kJ, and to maintain hydrogen bonds