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lana66690 [7]
3 years ago
10

The diagram above represents the melting of H2O(s). A 2.00mole sample of H2O(s) at 0°C melted, producing H2O(l) at 0°C. Based on

the diagram, which of the following best describes the amount of heat required for this process and the changes that took place at the molecular level?
Chemistry
1 answer:
sergejj [24]3 years ago
4 0
<h3>Answer</h3>

Heat : 12 kJ,  to maintain hydrogen bonds

<h3>Further explanation</h3>

Given

A 2.00mole sample ⇒ n = 2 mol

H₂O(s) at 0°C melted, producing H₂O(l) at 0°C

Required

the amount of heat required

the changes that took place

Analysis

Conversion of mol to mass

Use formula of Heat  :

Q = mLf (melting/freezing)  

Lf=latent heat of fusion  (for water=334 J/g)

Solution

mass H₂O(MW=18 g/mol) :

\tt mass=2\times 18=36~g

Heat required :

\tt Q=36\times 334=12024~J\approx 12~kJ

The absorbed heat is used to maintain hydrogen bonds in water molecules (there are two hydrogen bonds per molecule)

Paraphrase

The amount of heat required : 12 kJ, and to maintain hydrogen bonds

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A student who is performing this experiment pours an 8.50 mL sample of the saturated borax solution into a 10 mL graduated cylin
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Answer:

ksp = 0,176

Explanation:

The borax (Na₂borate) in water is in equilibrium, thus:

Na₂borate(s) ⇄ borate²⁻(aq) + 2Na⁺(aq)

<em>When you add just borax, the moles of Na²⁺ are twice the moles of borate²⁻, that means 2borate²⁻=Na⁺ </em><em>(1)</em>

The ksp is defined as:

<em>ksp = [borate²⁻] [Na⁺]²</em>

Then, borate²⁻(B₄O₇²⁻) reacts with HCl thus:

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The moles of HCl that reacts with B₄O₇²⁻ are:

0,500M×0,01200L = 6,00x10⁻³ mol of HCl

As two moles of HCl react with 1 mol of B₄O₇²⁻, the moles of B₄O₇²⁻ are:

6,00x10⁻³ mol of HCl×\frac{1molB_{4}O_{7}^{2-}}{2molHCl} = <em>3,00x10⁻³ mol of B₄O₇²⁻</em>

For (1), moles of Na⁺ are <em>3,00x10⁻³ mol ×2 = 6,00x10⁻³ mol of Na⁺</em>

The [borate²⁻] is <em>3,00x10⁻³ mol of B₄O₇²⁻/0,00850L = </em><em>0,353M</em>

And [Na⁺] is <em>6,00x10⁻³ mol of Na⁺ / 0,00850L = </em>0,706M

Replacing in the expression of ksp:

ksp = [0,353] [0,706]²

<em>ksp = 0,176</em>

<em></em>

I hope it helps!

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